Consider the double mass spring system shown in the figure below.wwwx₁ =197}The positions X₁ and x₂ of the two masses are given by the system[90-1*m2x2 ==197₂-(k₁ + K₂)k2X1][*]Xx2k₂-(k₂ + k3)+ F.Let m₁ = 1, m₂ = 1, k₁F₁=9 cos(6t) on the first mass and a force F2= 0 on the second and the masses startfrom rest ( x₁ (0) = x₂(0) = 0 ) and at their equilibrium positions ( x₁ (0) = x₂(0) = 0 ), findthe resulting motion of the system.=1, k₂ = 4 and k3 = 1. If the forcing imparts a force

The values are The initial condition are

Consider the double mass spring system shown in the figure below. M} m₁ The positions x₁ and x₂ of the two masses are given by the system [903-1* K] m₂ = 197₂ -(k₁+k₂) k₂ k2 −(k₂ + k3) X1 1[*] + F. Let m₁ = = 1, m₂ = 1, k₁ = 1, k₂ = 4 and k3 = 1. If the forcing imparts a force F₁ = 9 cos(6t) on the first mass and a force F₂ = 0 on the second and the masses from rest ( x (0) = x2(0) = 0 ) and at their equilibrium positions ( x₁ (0) = x₂(0) = the resulting motion of the system

Consider the double mass spring system shown in the figure below. M} m₁ The positions x₁ and x₂ of the two masses are given by the system [903-1* K] m₂ = 197₂ -(k₁+k₂) k₂ k2 −(k₂ + k3) X1 1[*] + F. Let m₁ = = 1, m₂ = 1, k₁ = 1, k₂ = 4 and k3 = 1. If the forcing imparts a force F₁ = 9 cos(6t) on the first mass and a force F₂ = 0 on the second and the masses from rest ( x (0) = x2(0) = 0 ) and at their equilibrium positions ( x₁ (0) = x₂(0) = the resulting motion of the system

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Q1: The system shown has two masses. Beam of mass (Jo#m L² kg.m²) rotates about fixed point (O) and its free end is connected to disk rotates about fixed point (O₂). Consider all connecting links are massless and rigid. Find 1- The displacements of points A, B, and C in addition to the rotations of masses, all in terms of 0. 2- Find the equation of motion (EOM) in terms of 0. 3- What is the natural frequency of the system? 0 L/2 8 Energy methods A Jo=m L²2 L/2 Joz-m R² R C B C 128
An eyebolt is subjected to four forces as shown in figure. F_{1} = 12kN F_{2} = 8kN F_{3} = 18kN , F_{4} = 4kN that act at angles of alpha_{1} = 45 deg , alpha_{1} = 45 deg alpha_{2} = 100 deg alpha_{3} = 205 deg alpha_{4} = 270 deg Determine the magnitude and direction of the resultant force
Determine the equivalent spring constant of the system shown in the figure.
k, k3 A В k2 What is the equivalent spring stiffness between the points A and B. If ki = 1 N/m, k2 =1 N/m. k3 = 2 N/m and k4 = 2 N/m A N/m
Consider the following spring system. with spring constants c 1 Cy Assume down is the positive direction. Write the elongation matrix A Write the stiffness matrix K
Find the equivalent spring constant spring constant of the system. Say, k1 = 20 lb/in, k2 = 35 lb/in, k3=18 lb/in,k4 = 50 lb/in, k5 = 45 lb/in
Find the equation of the following spring system. shaft k. disk -k,0 J
For the system shown in below figure, determine the equivalent spring constant in the direction of ϴ.
SHOW YOUR STEP BY STEP SOLUTION. 1. Assuming that the displacement (x) resulting from the application of a force F at a point A is small, find the equivalent spring constant of the system that relates the applied force F to the displacement x. k- 2k
4 = ½ = k = k k2 = 2 k kz = 3k F Derive the expression for the equivalent spring constant that relates the applied force F to the resulting displacement x of the system shown in the figure above. Assume the displacement of 1. the link to be small.
Consider the following spring system. 41 with spring constants c = 4 C2 4 Assume down is the positive direction. Write the stiffness matrix K = -24 Compute the displacements caused by the external forces f = 16 Displacement =
1. What is the equivalent stiffness of the system in the figure below using the displacement of the block as the generalized coordinate? E= 210 x 10' N 1= 1.5 x 10' m 5x 10°. 2.5 m 3 x zIE Z|E ZIE