Consider the code below and select all that apply: x=0 while True: if x%2==1: break X=X+2 print(x) O a. O b. O C. O d. O e. The iterating variable changes but it is always even. The loop is executed once and prints the value of x as 1. The iterating variable never changes. The break command is never called. This is an infinite loop.

Consider the code below and select all that apply: x=0 while True: if x%2==1: break X=X+2 print(x) O a. O b. O C. O d. O e. The iterating variable changes but it is always even. The loop is executed once and prints the value of x as 1. The iterating variable never changes. The break command is never called. This is an infinite loop.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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This test can only be taken once. Force Completion This test can be saved and resumed at any point until time has expired. The timer will continue to run if you leave the test. Your answers are saved automatically. • Show Timer ¥ Question Completion Status: QUESTION 1 What is the difference between a while loop and a do-while loop? O while loop checks the condition before the loop begins, whereas the do-while loop executes the body at least once before checking the condition. O while loop is used for counter-controlled and do-while, is used for a sentinel loop. O while loop is used for selection controlled and do-while is used for an infinite loop. O while loop is used for endless controlled control and do-while, is used for counter-controlled loop. Save All Ans Click Save and Submit to save and submit. Click Save All Answers to save all answers. DELL
True or False? In a do…while loop, the condition is checked at the bottom of the loop.
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Write a loop that runs 10 times. Note: You are not required to put anything inside the loop body.
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Q2: How do you know it break down the loop? which one is control it? Telling the detail.
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Assignment4B: Diamonds in the sky. In our earliest labs, we asked you to print a diamond pattern to the screen using predefined print statements. Now that we know how to use loops, we can make more dynamic and customizable patterns. For this assignment, we will prompt the user to enter a maximum width for the diamond. If they enter a number less than 3, we'll prompt them to choose a correct width. If they enter an even number (greater than 3), we will add 1 to it and let the user know the final diamond size. Then we will generate and print out the diamond using * and '' symbols. Hints: Each line of the "diamond" is made up of two parts – the asterisks in the center and the spaces to the left of it. The amount of "left space" decreases as we go towards the middle diamond, then increases afterwards as we go towards the bottom. Could we use multiple loops (or even nested loops) to model this behavior? Also, note that the number of asterisks increases (and later decreases) by two on each…
Output integer's digits Given an input positive integer, output each digit on its own line, starting with the rightmost digit. Ex: If the input is 935, the output is: 5 3 9 Hints: Use the mod operator (%) to get the rightmost digit. Mod by 10 to get the rightmost digit. Use a loop that keeps a current dividend (the number being divided). In each iteration, output the rightmost digit, then update the divisor by dividing by 10. End the loop when the divisor is 0. in java
"Simon Says" is a memory game where "Simon" outputs a sequence of 10 characters (R, G, B, Y) and the user must repeat the sequence. Create a for loop that compares the two strings starting from index 0. For each match, add one point to userScore. Upon a mismatch, exit the loop using a break statement. Assume simonPattern and userPattern are always the same length. Ex: The following patterns yield a userScore of 4:simonPattern: RRGBRYYBGY userPattern: RRGBBRYBGY #include <iostream>#include <string>using namespace std; int main() { string simonPattern; string userPattern; int userScore; int i; userScore = 0; cin >> simonPattern; cin >> userPattern; /* Your solution goes here */ cout << "userScore: " << userScore << endl; return 0;}