Consider the allyl radical (CH2CHCH2)' studied by the Hückel method. What is the TT-electronic energy ET of the molecule in the ground state? O a. a O b3α+ 3β OC. 30x+3/3B Od 3a-2/3B O ° 3a +2/2B
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- Calculate the wavelength pf light that is absorbed when a n electron in the molecule CH2=CH-CH=CH-CH=CH-CH=CH-CH=CH2 is promoted from the HOMO to the LUMO. The average bond length can be taken to be 144 pm. SHOW ALL YOUR WORK, INCLUDING HOW YOU CHOSE THE HOMO AND LUMO.H,SO, `OH + R T 180°С A но U NH3 W +If [CH4}) = 0.1M; [O2] = 0.25M\[CO2 ]= 0.35M and [H2O] = 0.15M what is the value of Qc?
- What is the molecular orbital structures of 1,4-pentadiene? What about 1,4-pentadiene radical?H&C OH H₂SO₁ CH,CH,CH,C-CHCH, H,SO, H₁C Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default. + CH 20 H± 2D EXP. CONT. Z1 A [1] Marvin JS by ChemAxon ΔΟ 0 0 0 0 0 A e Copyright 2024 B H C N о S CI Br - P LL FThe positions of the Br atoms in the molecule below is designated as Br -Br O meta O ortho O para O taro
- 3 Convert the following infrared wavelengths to cm-1. 3.38 mm, typical for a saturated C¬H bondA typical 1"B – 'H bond has a stretching frequency of 2400 cm1. Based on your understanding of isotopic effects on vibrational frequencies, and their connection to bond strength, rank the B - H bonds from weakest to strongest. Consider the most common isotopes of the B- H bonds highlighted below. Make sure to explain your ranking. 10В — 1н, 10В — ?н, 11в — 1Н, 11В - нUsing average bond enthalpies (linked above), estimate the enthalpy change for the following reaction: 2C0(g) + 02(g) 2CO2(g)
- 101 Chem101 C Chegg Search X b My Questions | bartleby X G Identify the LUMO in the MO di x G LUMO in the MO diagram of NC X + -> app.101edu.co M Apps G M Gmail YouTube Maps a AMAZON Translate Gflights USCIS Ь ВАТERBLY C CHEGG > KATAPULK CUBA SUPERMARKET23 Essay Writing Ser... G calculator - Googl... Reading List Question 5 of 22 Submit Identify the LUMO in the MO diagram of NO (shown below). A) o (2s orbitals) B) o (2pz orbitals) Op Tp C) TT (2px and 2py) D) T* (2px or 2py) E) o* (2pz) +The figure shows the molecular structure of allicin, a pungent substance found in garlic that inhibits the growth of bacteria like Staphylococcus aureus. H H 1| H 7| || :0: нн H H Analyze this substance by determining the electronic and molecular geometry of each numbered atom. Yegor Larin/Shutterstock; Revell, Introductory Chemistry, 2e, © 2021 W. H. Freeman and CompanyElectronic excitation of a molecule may weaken or strengthen some bonds because bonding and antibonding characteristics differ between the HOMO and the LUMO. For example, a carbon–carbon bond in a linear polyene may have bonding character in the HOMO and antibonding character in the LUMO. Therefore, promotion of an electron from the HOMO to the LUMO weakens this carbon–carbon bond in the excited electronic state, relative to the ground electronic state. Consult Figs. 9E.2 and 9E.4 and discuss in detail any changes in bond order that accompany the π*←π ultraviolet absorptions in butadiene and benzene.