Consider a simple spring mass damper system with m= 55X10A-3 kg, c- 0.12 kg/s, and k = 859 N/m. Calculate the value of the steady state response if w - 120 rad/s and to - 12 N/kg O A Natural frequency = 114.97 rad/s Damping ratio = 0.00973 Amplitude displacement for Steady state response (X) = 0.00864 m B. Damping ratio - 0.00773 Natural frequency 134.97 rad/s Amplitude displacement for Steady state response (X) 0.01964 m OC. Damping ratio - 0.00873 Natural frequency 124.97 rad/s Amplitude displacement for Steady state response (x) - 0.00964 m

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Consider a simple spring mass damper system with m=
55x10A-3 kg, c = 0.12 kg/s, and k = 859 N/m. Calculate the
value of the steady state response if w = 120 rad/s and fo
- 12 N/kg.
O A Damping ratio = 0.00973
Natural frequency = 114.97 rad/s
Amplitude displacement for Steady state response
(X) = 0.00864 m
Damping ratio = 0.00773
Natural frequency = 134.97 rad/s
Amplitude displacement for Steady state response
(X) = 0.01964 m
O C. Damping ratio = 0.00873
Natural frequency = 124.97 rad/s
Amplitude displacement for Steady state response
(x) = 0.00964 m
Transcribed Image Text:Consider a simple spring mass damper system with m= 55x10A-3 kg, c = 0.12 kg/s, and k = 859 N/m. Calculate the value of the steady state response if w = 120 rad/s and fo - 12 N/kg. O A Damping ratio = 0.00973 Natural frequency = 114.97 rad/s Amplitude displacement for Steady state response (X) = 0.00864 m Damping ratio = 0.00773 Natural frequency = 134.97 rad/s Amplitude displacement for Steady state response (X) = 0.01964 m O C. Damping ratio = 0.00873 Natural frequency = 124.97 rad/s Amplitude displacement for Steady state response (x) = 0.00964 m
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