Part CConsider a beam of electrons in a vacuum, passing through a very narrow slit of width2.00 µm. The electrons then head toward an array of detectors a distance 1.029 m away.These detectors indicate a diffraction pattern, with a broad maximum of electron intensity(i.e., the number of electrons received in a certain area over a certain period of time) withminima of electron intensity on either side, spaced 0.498 cm from the center of thepattern. What is the wavelength of one of the electrons in this beam? Recall that thelocation of the first intensity minima in a single slit diffraction pattern for light isy = LX/a, where L is the distance to the screen (detector) and a is the width of the slit.The derivation of this formula was based entirely upon the wave nature of light, so by deBroglie's hypothesis it will also apply to the case of electron waves.Express your answer in meters to three significant figures.ΑΣφ=SubmitRequest Answer

Wavelength of the electrons in the wave. given, slit widtha=2.0 μm=2.0×10-6 mDistanceL to the…

Consider a beam of electrons in a vacuum, passing through a very narrow slit of width 2.00 µm. The electrons then head toward an array of detectors a distance 1.029 m away. These detectors indicate a diffraction pattern, with a broad maximum of electron intensity (i.e., the number of electrons received in a certain area over a certain period of time) with minima of electron intensity on either side, spaced 0.498 cm from the center of the pattern. What is the wavelength A of one of the electrons in this beam? Recall that the location of the first intensity minima in a single slit diffraction pattern for light is y = L^/a, where L is the distance to the screen (detector) and a is the width of the slit The derivation of this formula was based entirely upon the wave nature of light, so by de Broglie's hypothesis it will also apply to the case of electron waves. Express your answer in meters to three significant figures. m Submit Request Answer

Consider a beam of electrons in a vacuum, passing through a very narrow slit of width 2.00 µm. The electrons then head toward an array of detectors a distance 1.029 m away. These detectors indicate a diffraction pattern, with a broad maximum of electron intensity (i.e., the number of electrons received in a certain area over a certain period of time) with minima of electron intensity on either side, spaced 0.498 cm from the center of the pattern. What is the wavelength A of one of the electrons in this beam? Recall that the location of the first intensity minima in a single slit diffraction pattern for light is y = L^/a, where L is the distance to the screen (detector) and a is the width of the slit The derivation of this formula was based entirely upon the wave nature of light, so by de Broglie's hypothesis it will also apply to the case of electron waves. Express your answer in meters to three significant figures. m Submit Request Answer

Modern Physics

3rd Edition

ISBN:9781111794378

Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer

Publisher:Raymond A. Serway, Clement J. Moses, Curt A. Moyer

Chapter5: Matter Waves

Section: Chapter Questions

Problem 13P

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