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Subnetting
Complete the given tables below:
| # of Subnets | # of hosts per subnet | Network Address of the first subnet | Network Address of the last subnet | Subnet Mask | |
| 1. 101.138.121.114 /22 --> /25 | |||||
| 2. 221.17.27.41 /24 ---> /26 | |||||
| 3. 65.120.65.162 /18 ---> 20 |
| #hosts | Subnet Mask in Binary | Subnet Mask in Decimal | Prefix |
| 35 | |||
| 1289 | |||
| 130 |
Step by step
Solved in 3 steps
- Design and implement an addressing scheme with a given network address: 172.32.0.0/18. Subnet the allocated prefix into 5 networks with 8 addressable host on the first 4 subnetworks, and 2 addressable host on the 5th subnetwork.Computer Science Networks and should be done in C language. Create a UDP client and server program that not only is able to locally transfer files but it gives the client the ability to send multiple copies of the file to multiple servers. Once the server program is initiated, it waits until it receives client packets. It then reads and saves the payload of the packets. The client reads a file from the disk and sends it to each server over a UDP socket by breaking the file up into mtu-byte sized packets. Client needs to be concurrent in sending the packets to all of the servers using threadsRefer to the following exhibit. R1(config)# aaa new-model R1 (config)# R1(config)# radius server Server-R R1(config-radius-server)# address ipv4 192.168.1.101 auth-port 1812 acct-port 1813 R1(config-radius-server) R1(config-radius-server) R1(config)# # key RADIUS-Pa55w0rd #exit Explain the reason(s) of specifying the ports being used for RADIUS and the key in the configuration. How could you include the RADIUS server as a AAA server?
- 7.1 In IEEE 802.11, open system authentication is accomplished via a simple two-way communication. The client requests authentication, which includes the station ID, which is provided by the server (typically the MAC address). A successful or unsuccessful authentication response from the AP/router is received in response to the previous request from the client. For instance, if the client's MAC address has been expressly omitted from the AP/router setup, a failure may occur.a. What are the advantages of using this kind of authentication scheme?b. What are the security flaws in this authentication method and how may they be mitigated?• IPV6 addresses use 128 bits to represent an address which includes bits to be used for subnetting. The second half of the address (least significant 64 bits) is always used for hosts only. Therefore, there is no compromise if we subnet the network. Use the Figure below to Create five subnets using route prefix 2001:db:acad::/48 (1 Marks) Routing Prefix Subnet ID Interface ID 48 Bits 16 Bits 64 BitsRefer the exhibit and the required number of hosts given. Subnet the address 192.168.50.0/24 for the required number of hosts using VLSM and complete the subnet table using the following instructions: NW: 192.168.50.0/24 NET-X: 45 USABLE HOSTS NET-Z: 2 USABLE HOSTS NET-Y: 25 USABLE HOSTS ------ GO/O R2 G0/0 GO/1 GO/1 R1 PC2 PC1 Assign the first subnet to network with the highest host requirement. Assign the second subnet to the network with the second highest host requirement. Assign the third subnet to the network with the third highest host requirement. Subnet Table: Subnet No. of Subnet First Last Usable Broadcast Subnet Name Usable Address Usable Host Address Mask hosts Host Address required Address
- 4 LANS are connected to a router (R1) with each LAN compares of several hosts connected to a switch. Each LAN cotains the following number of hosts (end devices and the gateway interface), • LANI à 30 Hosts • LAN2 à 15 Hosts • LAN3 à 20 Hosts • LAN4 à 3 Hosts You have received the address space 200.16.1.0/24. Use the address space to create a subnetting scheme of four subnets with equal size in a way to accommodate the number of hosts required. Consider the following points in your answer, / Explain the procedure of your subnetting scheme / Highlight the suitable prefix and the subnet mask / Highlight the number of wasted hosts in each subnet after determining the most suitable prefix / Use the table below to provide the subnet details for each LAN Subnet Address First Host address Last Host address Broadcast address 1 LANI 2 LAN2 3 LAN3 4 LAN4SUBNET ADDRESSING Consider the router and the two attached subnets below (A and B). The number of hosts is also shown below. The subnets share the 23 high-order bits of the address space: 144.145.110.0/23 : A 175 hosts QUESTION 2 OF 10 Answer How many hosts can there be in this address space? 144.145.110.0/23 B Assign subnet addresses to each of the subnets (A and B) so that the amount of address space assigned is minimal, and at the same time leaving the largest possible contiguous address space available for assignment if a new subnet were to be added. Then answer the questions below. 84 hostsComplete the given tables below: # of Subnets # of hosts per subnet Network Address of the first subnet Network Address of the last subnet Subnet Mask 1. 101.138.121.114 /22 --> /25 2. 221.17.27.41 /24 ---> /26 3. 65.120.65.162 /18 ---> 20 #hosts Subnet Mask in Binary Subnet Mask in Decimal Prefix 35 1289 130
- SUBNET ADDRESSING Consider the router and the two attached subnets below (A and B). The number of hosts is also shown below. The subnets share the 23 high-order bits of the address space: 144.145.110.0/23 175 hosts QUESTION 3 OF 10 A Answer What is the subnet address of subnet A? (CIDR notation) 144,145.110.0/23 Assign subnet addresses to each of the subnets (A and B) so that the amount of address space assigned is minimal, and at the same time leaving the largest possible contiguous address space available for assignment if a new subnet were to be added. Then answer the questions below. B 84 hostsIKT204-G H21, Routing tables 13 In this assignment, the objective is to determine the correct forwarding link given the routing table below. A router has the following entries in its forwarding table: Link1: 00001010.10101000.00000100.00000000/22 Link2: 00001010.10101000.00000110.00000000/23 Link3: 00001010.10101000.00000111.00000000/24 Link4: 00001010.10101000.00000000.00000000/16 Link5: All other addresses Assume the router receives IPV4 datagrams destined to the following addresses and decide which link they are forwarded to: A: 00001010.11111000.00000101.00001111 B: 00001010.10101000.00000111.00011000 C: 00001010.10101000.00000011.01010000 D: 00001010.10101000.00000111.11111110 E: 00001010.10101000.00000110.10000010 On which link will they be forwarded? A: link B: link C: link D: link E: linkSuppose you have a class C Network 200.94.115.0. Your task is to design a subnet scheme so that we can create 28 Network segments (subnets) within this Network. Each subnet should support hosts as given below. 2 Network Segment support 30 Hosts 4 Network Segment support 14 Hosts 8 Network Segment support 6 Hosts 14 Network Segment support 2 Hosts