Compare the slope in the picture with the literature value of 11,100 liter • mol-1 • cm-1. You will have to convert the slope in the picture to have the same units as the literature value. Clearly show how this unit conversion is done
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A: Molarity = number of moles of solute dissolved per litre of solution.
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A: The given expression is: 100 g1 mL10-3 L41.26 gmol8.4 molL=?
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Q: Match the units to the setup below for calculation of molarity X when dissolving a liquid X (X…
A: The number of moles of X is calculated as shown below. Thus, 1 is for 1 mol X and 2 is MW g X.
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A: Dilution equation: M1V1 = M2V2 where, M1 = Initial…
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A: H3PO4 Volume = 1920 cm³ = 1920 mL = 1.920 L Molarity = 1.76 × 10-³ M =1.76 × 10-³ mol/L Molarity =…
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A: Given that: Mass of diprotic acid = 0.045 g Volume of diprotic acid = 250 mL Molarity of NaOH =…
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A: 1) pH of HCl solution to be prepared =1.9
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A: Given-> Weight of diprotic acid = 0.278 gm Volume of flask= 250 ml = 0.250 L (1 L = 1000 ml)…
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A: Mass of solution = 500 g Mass Percentage = 10 % Mass of NaCl (salt) = ?
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A: Mass of the triprotic acid = 0.118 g Volume = 250 mL Molarity of NaOH = 0.1100 M Volume of NaOH…
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Q: An analytical chemist weighs out 0.185 g of an unknown monoprotic acid into a 250 mL volumetric…
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A: We need to use molarity equation to solve this question.
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Q: %3D .1 mL 441.)10 1 dt 10 I mL. %3D 441. 10 101 1°
A: So basically the question have asked to solve the unit conversation.
Q: A chemist prepares a solution of silver(I) nitrate (AGNO,) by measuring out 107. µmol of silver(1)…
A: Given data contains, Moles of silver nitrate is 107 μmol=107 μmol×1 mmole1000 μmol=0.107 mmol Volume…
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Q: A chemist prepares a solution of aluminum sulfite (Al, (SO,)) by measuring out 1.5 × 10" umol of…
A: Number of moles of solute present in 1 liter of solution is known as molarity of the solution.
Q: A chemist prepares a solution of aluminum sulfite (Al, (SO,)) by measuring out 179. µmol of aluminum…
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Q: An analytical chemist weighs out 0.206 g of an unknown monoprotic acid into a 250 mL volumetric…
A:
Q: A chemist prepares a solution of silver perchlorate (AgClO,) by measuring out 1.07 kg of silver…
A: Given, mass of AgClO4 = 1.07 kg = 1.07 × 1000 g = 1070 g Volume of the solution = 250 mL = 0.250 L…
Compare the slope in the picture with the literature value of 11,100 liter • mol-1 • cm-1. You will have to convert the slope in the picture to have the same units as the literature value. Clearly show how this unit conversion is done
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- A solution of FESCN2+ has a concentration of 1.00 x 10-2M and an absorbance of 0.755. What is the concentration of an FESCN2+ solution with an absorbance of 0.373? Enter your answer in scientific notation, with one decimal place, as follows: 2.3e-4 or 2.3E-4 Do not include units and note that 10 and x are NOT USED in this type of scientific notation.Please create a caption for this table. Solution NaCl Conc. (%) Osmolality (mOsm) % transmittance Absorbance % hemolysis % crenation C distilled 0 0 0.001029 4.987584625 100 0.03354 1 0.177179111 54.61 0.001551 4.809388202 96.42720001 0.05837 2 0.297126222 91.58 0.01012 3.994819487 80.09527231 0.08444 3 0.442542222 136.4 3.849 1.414652089 28.3634704 0.134 4 0.590164444 181.9 64.8 0.188424994 3.777880643 0.2125 5 0.74752 230.4 95.64 0.019360433 0.388172513 0.3368 6 0.89644 276.3 99.56 0.001915112 0.038397585 0.5336 7 1.095648889 337.7 99.98 8.68676E-05 0.001741676 0.9834 8 1.336711111 412 100 0 0 2.1 9 1.755568889 541.1 100 0 0 7.9 10 2.674395556 824.3 100 0 0 57.83 11 4.490211111 1384 100 0 0 99.72ASSAY Calibration solutions Calibration solutions of naproxen in the range 5 – 25 μg/mL were prepared. Sample preparation 20 tablets weighing 12.3819 g were crushed to a fine powder. A portion of the powder (145.4 mg) was shaken with approximately 150 mL of acetic acid (0.05 M) for 5 min and then made up to volume in a 250 mL volumetric flask (stock solution). Approximately 50 mL of the stock solution was filtered and a 25 mL aliquot was diluted to 100 mL in a volumetric flask. 10 mL of the resulting solution was further diluted to 100 mL with acetic acid (0.05 M). Analysis The standards and sample solutions were analyzed by HPLC under the following conditions: Column: octadecylsilyl (ODS), 4.6 mmx150 mm, mobile phase: acetonitrile : 0.05 M acetic acid (85:15), flow rate: 1 ml/min, UV detection at 243 nm. Results: A calibration curve of concentration versus peak area was constructed for the standard solutions and gave the straight-line equation: y = 3555.6x + 85, r = 0.9999 The area…
- How do I find Concentration? flask Calculate solution Concentration (M) Volume stock of 0.40 M CuSO4 (ml) Volume of flask (ml) Absorbance at 635 nm(a.u.) 1 2.0 10 .185 2 4.0 10 .362 3 6.0 10 .510 4 8.0 10 .674 5 10.0 10 .843Based on the given data, what is the λmax of cobalt? 0.1M Cobalt 300 0.451 325 0.467 350 0.584 375 0.629 400 0.694 425 0.673 450 0.541 475 0.433 500 0.423 525 0.327 550 0.264 575 0.245 600 0.233 625 0.211 650 0.189 675 0.187 700 0.165Current Attempt in Progress From the curves shown in Animated Figure and using the following Equation, determine the rate of recrystallization for pure copper at the several temperatures. Make a plot of In(rate) versus the reciprocal of temperature (in K-1). (a) Determine the activation energy for this recrystallization process. (See Section FACTORS THAT INFLUENCE DIFFUSION.) (b) By extrapolation, estimate the length of time required for 50% recrystallization at room temperature, 20°C (293 K). (a) i kJ/mol (b) i days
- A solution of FESCN2+ has a concentration of 1.00 x 10-M and an absorbance of 0.755. What is the concentration of an FeSCN2+ solution with an absodbance of 0.491? Enter your answer in scientific notation, with one decimal place, as follows: 2.3e-4 or 2.3E-4 Do not include units and note that 10 and x are NOT USED in this type of scientific notation. Question 3 of 26>»The following is a standard solution of phosphorus (P) data measured by a spectrophotometer. ppm P Absorbansi 2150 0.053 4260 0.110 6400 0.173 8520 0.220 A sample of 2.1 g Na2HPO4 is dissolved and diluted to a volume of 100 mL. The absorbance of the diluted solution was measured with a spectrophotometer and obtained an absorbance of 0.128. What is the percentage of phosphorus in the sample?STANDARD SAMPLE PREPARATIONS FOR ABSORBANCE & CONCENTRATION DATA Concentration of stock nickel sulfate hexahydrate solution = .400 Molarity Sample Volume Absorbance Concentration (In Molarity) a 5 mL .179 10 mL .329 15 mL .588 20 mL .760 25 mL .939 Reference Blank = 0 Please show how to find Molarity, please show steps. Thank you and stay safe.
- Help 100% 4A To Public Health Ch x * HSC 258 - Major Projec X MindTap - Cengage Lea X C The Illustration To TH d%=55750828934189288909969212&elSBN=9781305657571&id=D1061392007&nbld=21... * Q Search th References Use the References to access important values if needed for this question. For the following reaction, 24.7 grams of sulfur dioxide are allowed to react with 9.95 grams of oxygen gas . sulfur dioxide(g) + oxygen(g) → sulfur trioxide(g) What is the maximum mass of sulfur trioxide that can be formed? grams What is the FORMULA for the limiting reagent? grams What mass of the excess reagent remains after the reaction is complete? Submit Answery= mx+ b Slope () = -4E-09 y-intercept () = 0.4021 and OD= 0.540 , Calculate the concentration (x)0.3414 grams of sample (crushed aspirin tablet) was weighed and dissolved in 25 mL ethanol. This solution was transferred into a 100 mL volumetric flask and filled to the mark with deionized water. 20 mL of the solution was filtered through a 0.22 μm pore filter and 503 μL of the filtered sample solution was diluted so, that the final volume of the solution was 12 mL. This sample solution and calibration solutions with known concentration of acetyl salicylic acid (ASA) were injected (injection volume 20 μL) into a HPLC and the following peak areas were measured (expressed as averages from three separate chromatographic runs): Solution Cal 1 Cal 2 Cal 3 Cal 4 Cal 5 Sample Structure of ASA: C(ASA) (mg/L) 0 OH B 53.5 105.9 140.9 195.4 247.4 Average weight of the tablet was estimated as 591.9 mg. What is the mass of ASA in one tablet? Please give the answer with 4 significant digits. Be sure you present the result with units! Peak area (mA.s) 4995 9953 12941 17271 22179 10467.3