Explain this graph in your own words (200 words)? CeramicsMetals1000Composites- Tungsten- Iron/SteelSicAl,O3Si,N- Zrō2GlassCFRCTitaniumAluminumMagnesium100GFRCConcrete10PolymersWoodsPVCPS, Nylon1.0PTFEPE0.1Rubbers0.010.001Stiffness [Elastic (or Young's) Modulus (in units ofgigapascals)) (logarithmic scale)

Material Material is a mixture of substances which makes a object. Substances are made by molecules.…

Ceramics Metals 1000 Composites - Tungsten Iron/Steel Titanium SiC Al,0, Si,N. Zro2 CFRC 100 Aluminum Magnesium Glass GFRC Concrete 10 Polymers Woods PVC PS, Nylon 1.0 PTFE PE 0.1 Rubbers 0.01 0.001 Stiffness [Elastic (or Young's) Modulus (in units of gigapascals)] (logarithmic scale)

Ceramics Metals 1000 Composites - Tungsten Iron/Steel Titanium SiC Al,0, Si,N. Zro2 CFRC 100 Aluminum Magnesium Glass GFRC Concrete 10 Polymers Woods PVC PS, Nylon 1.0 PTFE PE 0.1 Rubbers 0.01 0.001 Stiffness [Elastic (or Young's) Modulus (in units of gigapascals)] (logarithmic scale)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A [0/90/0/±45]s Glass/Epoxy laminate is subjected to the following mechanical loads: Nx =Ny= 80*10^5 N/m. The thickness of each lamina is 0.25 mm. Longitudinal modulus of elasticity = E1 = 38.6 GPa , Transverse modulus of elasticity = E2 = 8.27 GPa , Poisons Ratio 0.26. a) Determine the local stresses at the top of 45° ply
ε = ce { 3. Assume the activation energy for the creep of Al2O3 is 425kJ/mol. (a) Predict the creep rate, &, for Al2O3 at 1000°C and 1800 psi applied stress. (See Table 6.12 for data at 1300°C and 1800psi.) (b) Calculate the lifetime of an furnace tube at 1000°C and 1800 psi if 1% total strain is permissible. (ε = 2.7x10-6/hr for Al2O3 at 1300°C and 1800psi.)
zain 1Q 2G 3G zain IQ Z Questions of Lectu... -> Questions of Lecture Four: Q1)) Answer the following briefly: What is means of Crystal structure? What the different between crystalline and amorphous structures? List the common lattice structures and give two examples for each? What the means of imperfections (defects) in the material crystals and why it happen? What are the differences between crystals imperfections types? How metallic crystals can deform elastically and plastically? Q2)) Fill the following blanks: A) Crystal structure can be found as -------- and ----------. B) Metals lattice structures are divide to -----, C) The three kinds of crystals imperfections can arise are --------, ---------, ----- Q3) Draw the following Point defects of crystals: (a) Vacancy, (b) ion-pair vacancy (Schottky), (c) interstitially, (d) displaced ion (Frenkel).
This is Materials/ Mechanics of Deformable Bodies Topic: Fundamentals of Stress and Strain Explain/describe in a concise and precise manner the relationship between stress and strain for both normal and shear. The needed: Normal stress, Normal Strain, Shear Stress, Shear Strain
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[Elastic Properties of Materials] There is a cylindrical bar of copper do in diameter is to be deformed elastically by application of a force along the bar axis. Using the data in Table given below, determine the normal force (F) that will produce an elastic reduction of Ad in the diameter. Use do 12.0 mm; Ad = d' - do = -3 × 10-³mm x = do 1 F d' l' Metal Alloy Aluminum Brass Copper Magnesium Nickel Steel Titanium Tungsten Modulus of Elasticity GPa 69 97 110 45 207 207 107 407 106 psi 10 14 16 6.5 30 30 15.5 59 Shear Modulus 106 psi GPa 25 37 46 17 76 83 45 160 3.6 5.4 6.7 2.5 11.0 12.0 6.5 23.2 Poisson's Ratio 0.33 0.34 0.34 0.29 0.31 0.30 0.34 0.28
[Elastic deformation after plastic deformation] A cylindrical specimen of a brass alloy has a diameter of d0 and alength of l. The tensile stress–strain behavior for this alloy is shown below. (1) The specimen is subjected to a tensile force of F1; then, the force is released. Compute the final length of thespecimen at this time.(2) The specimen is subjected to a tensile force of F2; then, the force is released. Compute the final length of thespecimen at this time.Use d0 = 7.0 mm; l = 90 mm; F1 = 5000N; F2 = 14200N
(6) There are many kinds of polyethylene foam, each with different properties. The low density polyethylene foams (as seen in this video) are very flexible. Remember: in solid mechanics, "flexible" just means that in comparison to other materials, the material deforms quite a bit, relative to the stress. For torsion, the material property that relates to stiffness is the shear modulus (or modulus of rigidity), G. We'll say that G = 6 MPa. a) Complete the FBD. b) Compute the shear stress at Point B. c) Illustrate it on a stress element. d) Report the shear strain at B (in radians). e) Compute the rotation of the top plane. f) Compute arc length s. FBD: I T=2 kN-m POINT B 18 300mm 1m
A polymer has creep behaviour that can be represented as a power law equation: e = 0 (Jo + Jit") where J, is 0.5 GPa1, J1 is 0.45 GPa's 0.3 and n is 0.3 (with t in seconds). A component of this material has the following applied stress history: There is no stress before t = 0 A positive (tensile) stress of 8 MPa is applied from t = 0 for 4 hours From t = 4 hours to 6 hours, the stress is compressive stress of 2 MPa The stress is then removed. What will the strain in the material be at t = 9 hours? Enter your value as a number to 4 decimal places. You have a 2% error margin with this.
In the appendices, the modulus of elasticity for silicon nitride is 304 GPa (that of steel is 207 GPa). How much porosity could be present in the round bar of silicon nitride such that it equals the reported value for steel?
QUESTION 3: [Thin-walled Pressure Vessels] 1. A cylindrical pressure vessel is fabricated from steel plating that has a thickness of 20 mm. The diameter of the pressure vessel is 450 mm, and its length is 2.0 m. Determine the maximum internal pressure that can be applied if the longitudinal stress is limited to 140 MPa, and the circumferential stress is limited to 60 MPa. 2. A compound thin cylinder has a common diameter of 100 mm, and the inner cylinder has a thickness of 2,5 mm. The radial pressure between the two cylinders is 200 kPa and the difference between the two common diameters before shrinkage was 4,305x 10-3 mm. E = 200 GPa. Determine a. Thickness of the outer cylinder b. Resultant hoop stresses in both cylinders if the compound cylinder is subjected to an internal pressure of 180 kPa.
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