Acceleration due to gravity near the surface of the earth can be considered constant, with a value of 9.80 m/s² downwards (towards the ground).a.b. Part AIf a ball is dropped from a height of d =29.0 m (as illustrated in "a," above) how long will i take for the ball to hit the ground?t =SSubmitPrevious AnswersNot completed before the time limitPart BSuppose that instead of being dropped, the ball is thrown downwards (as illustrated in "b." above) from the same height d =29.0 m ) and the ball hits the ground 1.46 s after it is thrown. What was the initialvelocity of the ball in this case?ΑΣφ?Vo =m/s

Part 1 Ball drop from height d=29m Acceleration due to gravity= 9.8m/s2 Initial velocity u= 0m/s…

Answered: celeration due to gravity near the…

celeration due to gravity near the surface of the earth can be considered constant, with a value of 9.80 m/s² downwards (towards the ground). a. b. d

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter6: Motion In Two Dimensions

Section6.3: Relative Velocity

Problem 27PP

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Question

Acceleration due to gravity near the surface of the earth can be considered constant, with a value of 9.80 m/s² downwards (towards the ground).
a.
b.

Part A
If a ball is dropped from a height of d =29.0 m (as illustrated in "a," above) how long will i take for the ball to hit the ground?
t =
S
Submit
Previous Answers
Not completed before the time limit
Part B
Suppose that instead of being dropped, the ball is thrown downwards (as illustrated in "b." above) from the same height d =29.0 m ) and the ball hits the ground 1.46 s after it is thrown. What was the initial
velocity of the ball in this case?
ΑΣφ
?
Vo =
m/s

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