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- Solutions of hydrogen in palladium may be formed by exposing Pd metal to H2 gas. The concentration of hydrogen in the palladium depends on the pressure of H2 gas applied, but in a more complex fashion than can be described by Henry's law. Under certain conditions, 0.94 g of hydrogen gas is dissolved in 215 g of palladium metal (solution density = 10.8 g cm3). (a) Determine the molarity of this solution. (b) Determine the molality of this solution. (c) Determine the percent by mass of hydrogen atoms in this solution.Lead poisoning has been a hazard for centuries. Some scholars believe that the decline of the Roman Empire can be traced, in part, to high levels of lead in water from containers and pipes, and from wine that was stored in leadglazed containers. If we presume that the typical Roman water supply was saturated with lead carbonate, PbCO3 (Ksp = 7.4 1014), how much lead will a Roman ingest in a year if he or she drinks 1 L/day from the container?6-40 What is the molarity of each solution? (a) 47 g of KCI dissolved in enough water to give 375 mL of solution (b) 82.6 g of sucrose, C12H22O11, dissolved in enough water to give 725 mL of solution (c) 9.3 g of ammonium sulfate, (NH4)2SO4 dissolved in enough water to give 2.35 L of solution
- A solution is made by dissolving 0.455 g of PbBr2 in 100 g of H2O at 50C. Based on the data in Table 8-1, should this solution be characterized as a. saturated or unsaturated b. dilute or concentratedA patient has a “cholesterol count” of 214. Like manyblood-chemistry measurements,this result is measured inunits of milligrams per deciliter (mgdL1). Determine the molar concentration of cholesterol inthis patient’s blood, taking the molar mass of cholesterolto be 386.64gmol1. Estimate the molality of cholesterol in the patient’sblood. If 214 is a typical cholesterol reading among men inthe United States, determine the volume of such bloodrequired to furnish 8.10 g of cholesterol.An unknown sample containing a mixture of NaCl and Na2CO3 was analyzed to determine the % composition of each compound. In the analysis for Na2CO3 (soda ash), the following data were obtained mass of unknown - 0.4436 g conc. of HCl used - 0.25 N initial volume - 0.5 mL final volume - 20.0 mL (MW soda ash) 106.12) 1.) What method was used to determine the concentration of HCl? 2.) What is the net volume of HCl used in the titration? 3.) What is % Na2CO3 in the given sample? NOTE: Round off your answer to a whole number (2 sig fig)
- POSSIBLE POIN Calculate the molarity of a solution that contains 80. grams of NaOH in 2.0 L of solution. Na = 23 g/mol O = 16 g/mol H = 1 g/mol 1 2 3 nisd schoology.com/common-assessment-delivery/start/483704 =onresume&submissionld=501882343 hp -> Ce @ #3 %24 & 3 4. 6. 8. 9. W e r y f h k dlmol How many moles of solute should be dissolved into 3.0 L of solvent to make a concentration of 2.0 M? /nisd.schoology.com/common-assessment-delivery/start/483704683 resume&submissionld=501882343# hp @ 4. 8. 9. y %23A cvg.cengagenow.com/ilrn/takeAssignment/takeCXPCompliantActivity.do?locator=Dassignment-take CHAPTER 4 - STOICHIOMETRY: QUANTITATIVE INFORMATION ABOUT CHEM OPrevious Page 5 of 9 Nex If you dilute 20.0 mL of 1.75 M hydrochloric acid to 700. mL, what is the molar concentration of the dilute acid? Molar concentration = nttps//als asp.cengage.info/als-asp/take
- An unknown sample containing a mixture of NaCl and Na2CO3 was analyzed to determine the % composition of each compound. In the analysis for Na2CO3 (soda ash), the following data were obtained mass of unknown - 0.4436 g conc. of HCl used - 0.25 N initial volume - 0.5 mL final volume - 20.0 mL (MW soda ash) 106.12) 1.) What method was used to determine the concentration of HCI? 2.) What is the net volume of HCI used in the titration? 3.) What is the % Na2CO3 in the given sample? NOTE: Round off your answer to a whole number (2 sig fig)3. The end point is the point where equal masses of reactants combine */^~²) False True 4. Calculate the molarity of 10 ml sample of vit. C solution if the volume of (0.01 M) I₂ solution required for complete reaction is 7.5 ml. * (1 Drint) 1.3 x 10 ² 1.3 x 10 7.5 x 10 3 7.5 x 10 6/viewer.html?state=%7B"ids"%3A%5B"1EMYPODX_-Kkn4ZIB78ytQoncxrZHwVo7%5D%2C"from"%3A'C e Kami Export - Bryce Carrington-$TOICHIOMETRY WORKSHEET#1 paf 6. Silver bromide can be precipitated through the following reaction. What mass of precipitate can be produced starting with 34.3 g of NaBr? NaBr + AGN03 NaNO3 + AgBr 7. How many moles of sodium bromide could be produced from 25.0 g of liquid Bromine? Bromine + Sodium iodide Sodium bromide + lodine