Calculate the density of FeO, given that it has the rock salt crystal structure. Note, the basis is two [i.e., 1 Fe2+ cation (r = 0.077 nm, A = 55.85 g/mol) and one O2− anion (r = 0.140 nm, A = 16 g/mol)] for this FCC structure (i.e., 4 lattice points), and NA = 6.022*10^23 formula units

Calculate the density of FeO, given that it has the rock salt crystal structure. Note, the basis is two [i.e., 1 Fe2+ cation (r = 0.077 nm, A = 55.85 g/mol) and one O2− anion (r = 0.140 nm, A = 16 g/mol)] for this FCC structure (i.e., 4 lattice points), and NA = 6.022*10^23 formula units

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter9: Liquids, Solids, And Materials

Section9.6: Crystalline Solids

Problem 9.9PSP

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Concept explainers

Crystal Lattices and Unit Cell

Consider a crystal. The regular and repeating pattern of constituent particles is the most distinguishing feature of crystalline solids. A crystal lattice is formed when these particles are replaced with representative points. The three-dimensional arrangement of constituent particles is known as a crystal lattice. Unit cell is that the smallest portion of a space lattice which when repeated in several directions, generate the whole lattice. Unit cell is a building block of a lattice. It is the smallest unit of cell.

Question

Calculate the density of FeO, given that it has the rock salt crystal structure. Note, the basis is
two [i.e., 1 Fe2+ cation (r = 0.077 nm, A = 55.85 g/mol) and one O2− anion (r = 0.140 nm, A =
16 g/mol)] for this FCC structure (i.e., 4 lattice points), and NA = 6.022*10^23 formula units
per mol. row = n' * (A sub F e+ A initial)/V sub c * N sub A

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