Bonus Question temperalures and the maximum reaction rate was determined from double reciprocal plot analysis. The data is presented below: A enzyme catalyzed reaction was performed at different Table 5 Temperature (deg K) 297.15 309.15 321.15 333.15 345.15 357.15 369.15 Vmax (mmol/hr) 0.60 1.40 3.00 7.00 17.00 8.40 0.48 From the data above, determine the slope of the temperature activation region and the slope of the temperature deactivation region. Then calculate the ratio of the slopes as (Slope)T deactivaUon (Slope)T activation Ratio = Note: the calculations in this problem can be completed without creating any plots. Slope (T activation) [mmol/{hr*deg K)] Slope (T deactivation) [mmol/(hr*deg K)] . Ratio
Bonus Question temperalures and the maximum reaction rate was determined from double reciprocal plot analysis. The data is presented below: A enzyme catalyzed reaction was performed at different Table 5 Temperature (deg K) 297.15 309.15 321.15 333.15 345.15 357.15 369.15 Vmax (mmol/hr) 0.60 1.40 3.00 7.00 17.00 8.40 0.48 From the data above, determine the slope of the temperature activation region and the slope of the temperature deactivation region. Then calculate the ratio of the slopes as (Slope)T deactivaUon (Slope)T activation Ratio = Note: the calculations in this problem can be completed without creating any plots. Slope (T activation) [mmol/{hr*deg K)] Slope (T deactivation) [mmol/(hr*deg K)] . Ratio
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter11: Rate Of Reaction
Section: Chapter Questions
Problem 71QAP: For a certain reaction, Ea is 135 kJ and H=45 kJ. In the presence of a catalyst, the activation...
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![Bonus Question (
temperalures and the maximum reaction rate was determined from double reciprocal plot
analysis. The data is presented below:
A enzyme catalyzed reaction was performed at different
Table 5
Temperature (deg K) 297.15 309.15
Vmax (mmol/hr)
333.15 345.15 357.15 369.15
0.48
321.15
0.60
1.40
3.00
7.00
17.00
8.40
From the data above, determine the slope of the temperature activation region and the slope of
the temperature deactivation region. Then calculate the ratio of the slopes as
(Slope)T dractivation
(Slope)T activation
Ratio
Note: the calculations in this problem can be completed without creating any plots.
Slope (T activation) [mmol/(hr*deg K)] .
Slope (T deactivation) [mmol/(hr*deg K)].
Ratio](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc4f433ca-3776-4ae1-b0d6-126a67fab1ec%2F418b43bf-c672-4c53-b7d3-c5e297d5241a%2Ffgm4wfl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Bonus Question (
temperalures and the maximum reaction rate was determined from double reciprocal plot
analysis. The data is presented below:
A enzyme catalyzed reaction was performed at different
Table 5
Temperature (deg K) 297.15 309.15
Vmax (mmol/hr)
333.15 345.15 357.15 369.15
0.48
321.15
0.60
1.40
3.00
7.00
17.00
8.40
From the data above, determine the slope of the temperature activation region and the slope of
the temperature deactivation region. Then calculate the ratio of the slopes as
(Slope)T dractivation
(Slope)T activation
Ratio
Note: the calculations in this problem can be completed without creating any plots.
Slope (T activation) [mmol/(hr*deg K)] .
Slope (T deactivation) [mmol/(hr*deg K)].
Ratio
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