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(b) What is the p-value for the test? (Use technology to find the p-value. Round your answer to four decimal places.) p-value = 0.0719 (c) Suppose the sample standard deviation of serum creatinine in part (a) is 0.7 mg/dL. Assume that the standard deviation of serum creatinine is not known, and perform the hypothesis test in part (a). Report a p-value. Find the test statistic. (Round your answer to two decimal places.) 1.03 ✓ Use technology to report a p-value. (Round your answer to four decimal places.) p-value = 0.3233 State your conclusion. ⒸFail to reject Ho. There is insufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. O Reject Ho. There is insufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. O Reject Ho. There i sufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. O Fail to reject Ho. There is sufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. (d) Compute a two-sided 95% CI for the true mean serum-creatinine level (in mg/dL) in part (c). (Enter your answer using interval notation. Round your numerical values to two decimal places.) (0.92,1.48) X mg/dL

(b) What is the p-value for the test? (Use technology to find the p-value. Round your answer to four decimal places.) p-value = 0.0719 (c) Suppose the sample standard deviation of serum creatinine in part (a) is 0.7 mg/dL. Assume that the standard deviation of serum creatinine is not known, and perform the hypothesis test in part (a). Report a p-value. Find the test statistic. (Round your answer to two decimal places.) 1.03 ✓ Use technology to report a p-value. (Round your answer to four decimal places.) p-value = 0.3233 State your conclusion. ⒸFail to reject Ho. There is insufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. O Reject Ho. There is insufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. O Reject Ho. There i sufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. O Fail to reject Ho. There is sufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. (d) Compute a two-sided 95% CI for the true mean serum-creatinine level (in mg/dL) in part (c). (Enter your answer using interval notation. Round your numerical values to two decimal places.) (0.92,1.48) X mg/dL

Algebra for College Students
Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter10: Exponential And Logarithmic Functions
Section10.6: Exponential Equations, Logarithmic Equations, And Problem Solving
Problem 56PS
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(b) What is the p-value for the test? (Use technology to find the p-value. Round your answer to four decimal places.) p-value = 0.0719 (c) Suppose the sample standard deviation of serum creatinine in part (a) is 0.7 mg/dL. Assume that the standard deviation of serum creatinine is not known, and perform the hypothesis test in part (a). Report a p-value. Find the test statistic. (Round your answer to two decimal places.) 1.03 Use technology to report a p-value. (Round your answer to four decimal places.) p-value = 0.3233 ✔ State your conclusion. ● Fail to reject Ho. There is insufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. O Reject Ho. There is insufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. O Reject Ho. There is sufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. O Fail to reject Ho. There is sufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. (d) Compute a two-sided 95% CI for the true mean serum-creatinine level (in mg/dL) in part (c). (Enter your answer using interval notation. Round your numerical values to two decimal places.) (0.92,1.48) X mg/dL
Transcribed Image Text:(b) What is the p-value for the test? (Use technology to find the p-value. Round your answer to four decimal places.) p-value = 0.0719 (c) Suppose the sample standard deviation of serum creatinine in part (a) is 0.7 mg/dL. Assume that the standard deviation of serum creatinine is not known, and perform the hypothesis test in part (a). Report a p-value. Find the test statistic. (Round your answer to two decimal places.) 1.03 Use technology to report a p-value. (Round your answer to four decimal places.) p-value = 0.3233 ✔ State your conclusion. ● Fail to reject Ho. There is insufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. O Reject Ho. There is insufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. O Reject Ho. There is sufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. O Fail to reject Ho. There is sufficient evidence to conclude that the mean serum-creatinine level in this particular group of patients is different from that of the general population. (d) Compute a two-sided 95% CI for the true mean serum-creatinine level (in mg/dL) in part (c). (Enter your answer using interval notation. Round your numerical values to two decimal places.) (0.92,1.48) X mg/dL
Renal Disease The mean serum-creatinine level measured in 13 patients 24 hours after they received a newly proposed antibiotic was 1.2 mg/dL. You can use SALT to answer parts of this question.
Transcribed Image Text:Renal Disease The mean serum-creatinine level measured in 13 patients 24 hours after they received a newly proposed antibiotic was 1.2 mg/dL. You can use SALT to answer parts of this question.
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