(b) Implement a function in Python to create a dictionary: {'a': 10, 'b': 20, 'c': 30, 'd': 40} and display each key-value pairs of it. Implement a function dict_check_add(dictionary, key, value) in Python to check whether a key of the given key-value pair already exists in the dictionary. If it is not, add the key-value pair to the dictionary.
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- Python Write a function print_dict to print all the key-values in a dictionary, for example: >>> d2 {'a': 'one', 'b': 'two', 'c': 'Three'} >>> print_dict(d2) a:one b:two c:ThreeWrite a function find_key(input_dict, target_value) that takes as parameters a dictionary and a target value and returns the key in the dictionary that maps to the target value or None if no such key exists. In other words, the function finds the key such that input_dict[key] == target_value. Notes: You may assume that the target_value only appears once in the dictionary and therefore there will be only one key that maps to the target. Hint: You need to iterate over all the keys, as this task is effectively using the dictionary backwards. For example: Test Result test_dictionary = {100:'a', 20:'b', 3:'c', 400:'d'} print(find_key(test_dictionary, 'b')) 20 test_dictionary = {100:'a', 20:'b', 3:'c', 400:'d'} print(find_key(test_dictionary, 'e')) NoneIn Python: make_dict(n) Write a function called `make_dict(n)`, where n is an integer parameter. With a given number n, make a new dictionary in your function where the keys in the dictionary are in the range from 1 to n, and value for each key is the square of the key for that entry. Your function should return this dictionary, not print it. main() Call `make_dict(n)`, where the user is asked to specify a number to pass into `make_dict(n)`, and then prints the returned dictionary object.
- python: def traditions_dict(adict): """ Question 6 Given a dictionary that maps a person to a list of their favorite traditions, return a dictionary with the value being the list sorted by the last letter of each tradition. If two traditions have the same last letter, sort by the first letter. HINT: This will require the use of lambda functions Args: adict (dict) Returns: dict >>> traditions_dict({"Jacob": ["The Horse", "Stealing the t", "Midnight Bud"], "Athena": ["Mini Five-Hundred", "Freshman Cake Race", "Buzzweiser Song"], "Liv": ["Freshman Cake Race", "George P. Burdell", "Buzzweiser Song"]}) {'Jacob': ['Midnight Bud', 'The Horse', 'Stealing the t'], 'Athena': ['Mini Five-Hundred', 'Freshman Cake Race', 'Buzzweiser Song'], 'Liv': ['Freshman Cake Race', 'Buzzweiser Song', 'George P. Burdell']} >>> traditions_dict({"Madison": ["The Horse", "Midnight Bud", "Buzzweiser…create a function in python parameters: 1. dict[str, list[str]] 2. list[str] return type: dict[str, list[str]] must do like this: 1. establish an empty dictionary that will serve as the dictionary returned at the end 2. loop thorugh each of the columns in the second parameter of the function 2a. asssign to the column key of the result dictionary the list of values stored in the input dictionary at the same column 3. return the dictionary produced do not import other libraries such as pandas, .select, .head, .iloc or anything this function is being used to work in a dataframepython: answer in one line of code if possible, please def traditions_dict(adict): """ Question 6 Given a dictionary that maps a person to a list of their favorite GT traditions, return a dictionary with the value being the list sorted by the last letter of each tradition. If two traditions have the same last letter, sort by the first letter. HINT: This will require the use of lambda functions Args: adict (dict) Returns: dict >>> traditions_dict({"Jacob": ["The Horse", "Stealing the t", "Midnight Bud"], "Athena": ["Mini Five-Hundred", "Freshman Cake Race", "Buzzweiser Song"], "Liv": ["Freshman Cake Race", "George P. Burdell", "Buzzweiser Song"]}) {'Jacob': ['Midnight Bud', 'The Horse', 'Stealing the t'], 'Athena': ['Mini Five-Hundred', 'Freshman Cake Race', 'Buzzweiser Song'], 'Liv': ['Freshman Cake Race', 'Buzzweiser Song', 'George P. Burdell']} >>>…
- Define a Python function which creates a dictionary where the keys are between the letters “a” and “h”, inclusive, and the values are square of keys’ ordinal value (Hint: check an ASCII table). The function should return the dictionary back to the caller. • Using the returned dictionary from your function, print the entire dictionary.• Using the returned dictionary from your function, print only the values of the dictionary.• Using the returned dictionary from your function, print only the keys of the dictionary.Write a function, young_john(people), that returns True if the dictionary people contains the key "John" with a value of 19. It should return False otherwise. like this def young_john(people):In python implement the build_dictionary() function to build a word frequency dictionary from a list of words. Ex: If the words list is: ["hey", "hi", "Mark", "hi", "mark"] the dictionary returned from calling build_dictionary(words) is: {'hey': 1, 'hi': 2, 'Mark': 1, 'mark': 1} Ex: If the words list is: ["zyBooks", "now", "zyBooks", "later", "zyBooks", "forever"] the dictionary returned from calling build_dictionary(words) is: {'zyBooks': 3, 'now': 1, 'later': 1, 'forever': 1} The main code builds the word list from an input string, calls build_dictionary() to build the dictionary, and displays the dictionary sorted by key value.
- In python: Problem Statement:The program takes a string and creates a dictionary with key as first character and value as thecount of letter in the string and also, sort the dictionary w.r.t the values of count in descendingorder. Pseudocode:Start of build_dict function An empty dictionary is declared Start of for loop to traverse through the letters of the string If letter is not present as a key in the dictionary The letter is initialized as the key and assign 1 to it ( since initially the count would be 1) Else The value of the letter as key in the dictionary is increased by 1 End of build_dict function Sort the dictionary and assign it back to the same dictionary variableStart of print_dict function Iterate over all the items of the dictionary Print the key and valueEnd of print_dict function Start of main function User must enter a large string and store it in a variable Call the build_dict function with string parameter and return…Please answer it in Python Write a function incrementer_scores that takes two dictionaries as arguments score_total and score_partiel of the same format used to count scores. The function modifies the dictionary score_total to add to each player the number of points appearing in score_partiel. This function will be used for example to put updates player scores after a round of play. For example, if the dscores dictionary contains {'tata': 3, 'titi': 12, 'toto': 0}, t hen, after calling incrementer_scores(dscores, {'titi': 1, 'toto': 0, 'tata': 11}), t he dscores dictionary will contain {'tata': 14, 'titi': 13, 'toto': 0}13. While dictionaries are designed so that we can find a value based on a key, every so often we need to perform a reverse lookup. For example, imagine a dictionary where the keys are names and the values are phone numbers. Usually we want to find the phone number based on the name, but occasionally you might need to find a name based on the phone number. Write a function called reverse_lookup(dictionary, value) that returns all the keys in the dictionary associated with the specified value. Note: In dictionaries, the keys are guaranteed to be unique, but the values are not. So your function should return a list containing all of the matching keys (if any) Example: Given this dictionary, groups = {'Apple': 'Fruit', 'Spinach': 'Vegetable', 'Banana': 'Fruit'} reverse_lookup (groups. Vegetable') ["Spinach'] reverse_lookup (groups, Fruit') ['Apple'. 'Banana'] reverse_lookup (groups. 'Meat') []