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Attached to one end of a vertical wall is a 1120N uniform beam that is held up by a cable at the other end. At the far end of the beam hangs a 1960N crate.  Using the attached image, please answer the following questions: Why is the direction of Fv facing up instead of down? In order to find the value of FT, where should the pivot point be placed in the image below? Since we don't have the length of the beam, we know that is a uniform beam. If the length of the beam is L, what's the distance from the pivot to where the 1220N weight is hanging? and the length to where FT and the 1960N weight is? In order to find torques, What is the angle between FT and the beam? What is the angle between the weights and the beam?

Attached to one end of a vertical wall is a 1120N uniform beam that is held up by a cable at the other end. At the far end of the beam hangs a 1960N crate.  Using the attached image, please answer the following questions: Why is the direction of Fv facing up instead of down? In order to find the value of FT, where should the pivot point be placed in the image below? Since we don't have the length of the beam, we know that is a uniform beam. If the length of the beam is L, what's the distance from the pivot to where the 1220N weight is hanging? and the length to where FT and the 1960N weight is? In order to find torques, What is the angle between FT and the beam? What is the angle between the weights and the beam?

University Physics Volume 1
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter2: Vectors
Section: Chapter Questions
Problem 21CQ: What is wrong with the following expressions? How can you correct them? (a) C=AB , (b) C=AB , (c)...
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Attached to one end of a vertical wall is a 1120N uniform beam that is held up by a cable at the other end. At the far end of the beam hangs a 1960N crate.  Using the attached image, please answer the following questions:

  1. Why is the direction of Fv facing up instead of down?
  2. In order to find the value of FT, where should the pivot point be placed in the image below?
  3. Since we don't have the length of the beam, we know that is a uniform beam. If the length of the beam is L, what's the distance from the pivot to where the 1220N weight is hanging? and the length to where FT and the 1960N weight is?
  4. In order to find torques, What is the angle between FT and the beam? What is the angle between the weights and the beam?
  5. Find the tension force.
  6. Since you now know the tension force, find the forces FV and FH using Newton's 2nd law.
Fr 50.0 Beam Fv 1960N 300 FH 1220N 960 N "1960 |
Transcribed Image Text:Fr 50.0 Beam Fv 1960N 300 FH 1220N 960 N "1960 |
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