At the beginning of the lesson, the radical function S=15.9 Lf was introduced, where 'S' is the speed of the vehicle in km/h, 'L' is the length of the skid marks in meters, and 'f' is the coefficient of friction. The coefficient of friction for a particular road made of asphalt pavement is 0.80. The new function would be S=15.9√0.80L Determine the length of the skid mark if the vehicle was travelling 52km/h. a. 102.6 m b. 13.4 m c. 8.6 m d. 2.26 m

College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter3: Functions
Section3.7: Inverse Functions
Problem 46SE: The circumference C of a circle is a function of its radius given by C(r)=2r. Express the radius of...
Question
At the beginning of the lesson, the radical function S=15.9 Lf was introduced, where 'S' is
the speed of the vehicle in km/h, 'L' is the length of the skid marks in meters, and 'f' is the
coefficient of friction. The coefficient of friction for a particular road made of asphalt pavement
is 0.80. The new function would be S=15.9√0.80L
Determine the length of the skid mark if the vehicle was travelling 52km/h.
a. 102.6 m
b. 13.4 m
c. 8.6 m
d. 2.26 m
Transcribed Image Text:At the beginning of the lesson, the radical function S=15.9 Lf was introduced, where 'S' is the speed of the vehicle in km/h, 'L' is the length of the skid marks in meters, and 'f' is the coefficient of friction. The coefficient of friction for a particular road made of asphalt pavement is 0.80. The new function would be S=15.9√0.80L Determine the length of the skid mark if the vehicle was travelling 52km/h. a. 102.6 m b. 13.4 m c. 8.6 m d. 2.26 m
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