Any of the types of distillation we use to separate a medicinal substance dissolved in a mixture of solvents consisting of Diethylether, Dichloromethane and Dimethylsulfoxide, knowing that the substance loses its medicinal effectiveness when exposed to a temperature higher than 15OC.
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- Hexanoic acid was added to an immiscible biphasic solvent sysem, water and CCl4 at 20.0OC and the equilibrium concentrations of hexanoic acid were determined to be 3.66 g/L in H2O and 67.0 g/L in CCl4. Caluclate the distrubution coeffiecent (D1) of hexanoic acid in CCl4 with respect to water.10:31 „0. O O ? 86%i E AIATS For Two Year Medic... A 87 /180 (02:53 hr min Mark for Review The correct order of ease of dehydration of the following compounds is CH, (а) CН,-С - Он CH3 CH3 (b) CH, - CH - OH (c) CH3CH2OH a > b >c b>c> a a >c > b c > b > a Clear Response IIIHow to prepare 250cm3 of a solution of carbonate with concentration 0.100 mol dm-3
- pneumonia is characterized by fever (a body temperature) does the patient have a body temperturr that indicates that he has pneumonia? justify your answer with suitable caculation PLEASE.13. In which of the following organic solvents do you expect methane (CH4) to be most soluble? The structure of glucose is shown on the right. (a) (b) (d) Η Η Η Η Η TIT H=C=C=C=C=C-H | Η Η Η Η Η Η Η Η Η Η TI H=C=C=C=C=C-OH TI Η Η Η Η Η Η Η Η Η Η ||||| HO-C-C-C-C-C-OH Η Η Η Η Η Η Η Η Η TIT H=C=C=C=C=C-Cl | Η Η Η Η Η Η ΗDefi ne moist and dry heat, and explain their modes of action and relative eff ectiveness.
- A chemist is asked to separate the components of a mixture composed of 1.00 g each of the two compounds shown below. The chemist has access to the following bases: 10% aqueous NaHCO3 and 10% aqueous NaOH. Which base and how many mLs of the base (i.e., the minimum amount) are needed to completely separate these compounds from each other by liquid-liquid extraction?11. Four biochemical engineers were each given a chlorine-containing hydrocarbon to analyze and react with three different reagents. Their distribution is as follows: [a.] Engr. Consigo was given 52 mL of chloromethylcyclohexane [b.] Engr. Marchadesch acquired 1.0 L of 6.3 M chlorocyclopentane [c.] Engr. Bauzon had 9.12 cubic centimeters of 1-chloro-1-methyl-cyclopentane If they were to react each of there samples with: (1.) Sodium Acetate, (2.) Sodium Methoxide, and (3.) Potassium tert- butoxide, Draw the skeletal structures of the major product for each reaction. In the case that the major product could not be inferred, draw the all of the products in the resulting mixture.True or False: Carboxylic acids containing six or more carbon atoms per molecule are more soluble in 3 M sodiumaqueous hydroxide than in dichloromethane.
- Determine the values of Kc that correspond to the following values of Kp. 1.) SO2CI2(g)—›‹—SO2(g)+CI2(g) Kp=2.9×10^-2 at 303K 2.) 2 NO2(g)—›‹— 2 NO(g)+O2(g) Kp=0.275 at 700k 3.) CO(g)+CI2(g)—›‹—COCI2(g) Kp=22.51-Pentanol to 1-bromopentane Chemicals: - 60ml Conc. Sulfuric Acid - 100ml Saturated Sodium bicarbonate - 65ml 1-Pentanol - 78g sodium bromide - Distilled water - 58.42g 1-Bromopentane 1-Pentanol Sodium Bromide Sulfuric Acid 1-Bromopentane Formula C5H12O NaBr H2SO4 C5H11Br MW (g/mol) 88.15 102.894 98.078 151.04 Density (g/mL) 0.811 3.21 1.84 1.218 Boiling point (*C) 138 1,396 337 130 NaBr(aq) + H2SO4(aq) -> NaHSO4(aq) + HBr(aq) CH3(CH2)4OH(aq) + H+ Br- (aq) CH3(CH2)4OH2 (aq) + Br-(aq) CH3(CH2)4OH2 (aq) + Br-(aq) CH3(CH2)4Br(aq) + H2O(aq) How do I calculate the percent yield and identify the limiting reagent?Write the expression for Keq for the following reactions. In each case indicate whether the reaction is homogeneous or heterogeneous.(a) N2(g) + 3 H2(g) 2 NH3(g) Keq = PNH32 / (PN2 PH23) Keq = (PN2) (3 PH2) / 2 PNH3 Keq = PN2 PH23 / PNH32 Keq = 2 PNH3 / ((PN2) (3 PH2)) The reaction is (b) 4 HCl(g) + O2(g) 2 H2O(l) + 2 Cl2(g) Keq = PHCl4 PO2 / PCl22 Keq = 2 PCl2 / (4 PHCl PO2) Keq = 4 PHCl PO2 / 2 PCl2 Keq = PCl22 / (PHCl4 PO2) The reaction is (c) H2(g) + I2(g) 2 HI(g) Keq = 2 PHI / (PH2 PI2) Keq = PH2 PI2 / 2 PHI Keq = PH2 PI2 / PHI2 Keq = PHI2 / (PH2 PI2) The reaction is