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Answer TWO branches (aq) +Fe(s) → Cu(qa) + Fe2+ Cu2+ A/ By calculation E and AG for the reaction (aq), E' Cu²+/Cu = 0.34, E° Fe2+/Fe=(-0.44) volt, predict if the reaction is spontaneous or not? B/By details balance the following acidic redox reaction. Cu + NO3¹ → NO + Cu²+ C/ Calculate the molar solubility of barium fluoride BaF2 (Ks.p=1×106) in a solution contains (0.15M) NaF?

Answer TWO branches (aq) +Fe(s) → Cu(qa) + Fe2+ Cu2+ A/ By calculation E and AG for the reaction (aq), E' Cu²+/Cu = 0.34, E° Fe2+/Fe=(-0.44) volt, predict if the reaction is spontaneous or not? B/By details balance the following acidic redox reaction. Cu + NO3¹ → NO + Cu²+ C/ Calculate the molar solubility of barium fluoride BaF2 (Ks.p=1×106) in a solution contains (0.15M) NaF?

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter19: Principles Of Chemical Reactivity: Electron Transfer Reactions
Section19.5: Electrochemical Cells Under Nonstandard Conditions
Problem 19.7CYU: The half-cells Ag+(aq. 1.0 M)|Ag(s) and H+(aq, ? M)|H2(1.0 bar) are linked by a salt bridge to...
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Answer TWO branches (aq) +Fe(s) → Cuqa) + Fe2+ (aq), Cu2+ spontaneous or not? A/ By calculation E and AG for the reaction E' Cu²+/Cu = 0.34, E° Fe2+/Fe=(-0.44) volt, predict if the reaction is B/By details balance the following acidic redox reaction. Cu + NO3¹ → NO + Cu²+ C/ Calculate the molar solubility of barium fluoride BaF2 (Ks.p=1×106) in a solution contains (0.15M) NaF?
Transcribed Image Text:Answer TWO branches (aq) +Fe(s) → Cuqa) + Fe2+ (aq), Cu2+ spontaneous or not? A/ By calculation E and AG for the reaction E' Cu²+/Cu = 0.34, E° Fe2+/Fe=(-0.44) volt, predict if the reaction is B/By details balance the following acidic redox reaction. Cu + NO3¹ → NO + Cu²+ C/ Calculate the molar solubility of barium fluoride BaF2 (Ks.p=1×106) in a solution contains (0.15M) NaF?
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