Analyse the frame as shown in fig. 3 below by using Moment distribution method. And Draw BMD and SFD. 20 kN/m 20 20 6 kN- ⑪ 2D 1 m 1 m 6 kN 3 m Φ 3 m A mmm 2 m Fig. 3 mmmm D

The beam has a moment of inertia of I = 125(106) mm². Determine the slope of the beam at B. E= 200 GPa. Use the method of virtual work. 18 kN - m A -4m- B ID C I -3 m- -3 m- 20120 -4 m- 18 kN m

Deflection of Beams Use Conjugate Beam Method Given: X - 274 у-74 а-8 b - 4 C- 9 Y kN X kN 2m 1 F 2m B 10 + B 1. What is the reaction at A? (kN) 2. What is the reaction at B? (kN) 3. What is the deflection at a point 2 m from A? (N/m³)/EI 4. What is the deflection at a point 2 m from B? (N/m³)/EI 5. What is the slope at a point 2 m from A? (N/m²)/EI 6. What is the slope at a point 2 m from B? (N/m²)/EI 7. At what distance from A will the maximum deflection of the beam occur? (m) 8. What is the maximum deflection on the beam? (N/m³)/EI

Deflection of Beams Use Virtual work Method Given: X - 274 у-74 а-8 b - 4 с- 9 Problem #1 #1 Determine the vertical displacement of joint A. Each bar is made of steel and has a cross-sectional area of 600 mm². Take E = 200 GPa. -1.5 m- -1.5 m- P = X a = A

Deflection of Beams Use Conjugate Beam Method Given: X - 274 у-74 а-8 b - 4 C- 9 Y kN/m 10 m 9. What is the reaction at A? (kN) 10. What is the deflection at a point 2 m from A? (N/m³)/EI 11. What is the deflection at a point 2 m from B? (N/m³)/EI 12. What is the slope at a point 2 m from A? (N/m²)/EI 13. What is the slope at a point 2 m from B? (N/m²)/EI 14. At what distance from A will the maximum deflection of the beam occur? (m) 15. What is the maximum deflection on the beam? (N/m³)/EI

SOLVE PLEASE Ar A HINT: Figure 5 R₁ V₁ 1 Max - Calculate the balance of the beam by superposition method Make the shear and moment diagram (Analytical method) - Calculate by double integration -.57741->> Shear 22/3 W Moment TUTO B R₁₂ V₂ Simple Beam - Load Increasing Uniformly to One End 4/3 R₁ = V₁ R₂ = V₂ DAB YAB M, V₂ M. (x = = 57740). +3 at 3 Amax at x = ₁ 6/1-18 = 15 W = 1.6 = .5193€ L = 3.2 W 3 2W 3 W 3 2We 9√3 Wx 36² Wx² e² = .1283We -(²-x²) We' ΕΙ = .01304- Wx 180EIC² -(3x4 10l²x² +7(4)

EI = 3 * 10 KN.m² Q₁/ For the beam shown in fig. (1). Find all moments (Use S.D.M.) 100KN 20KN/m 20KN I 21 5m A 0.02 hadd 2m 2m B. 15mm Fig. (1) 1.5m

UAB = 1 wac = ? *16-60 The slider block C moves at 8 m/s down the inclined groove. Determine the angular velocities of links AB and BC, at the instant shown. Cotohon around a fixed ³8 = WAR X PAB cand off = _WAB K x (2i) = -2WABj →general plane of motion → √₂ = vc + BCB/C - 2 m -2WABJ = 8 sinus 18 twBck * 25 FB/1C 45 A 45° TAB WAB # B ль BIC 2 m SUBC с 45 Vc = 8 m/s 8 $145 T

Homeworks: A steel shaft of two segments AB and BC which are rigidly fastened at B Determine: 1) Reactions at A and C. 2) Maximum angle of rotation. 1000N. mn/mm 4m 100mm S0mm 5mm

determine the rotation and vertical deflection at point C for the beam shown in Figure(1). 6 kips 1. Figure (1) 21 B. E-29000ksi F1000in 15.0ft- -15.0n