An optical fiber with circular cross section has refractive index 1.45. It’s surrounded by a cladding with refractive index 1.43. (a) Find the maximum angle relative to the fiber axis at which light can propagate down the fiber by undergoing successive to-tal internal reflections. (b) Find the speed of light in the fiber. (c) For the angle you found in part (a), find the speed at which light actually makes its way along the fiber—that is, the length of fiber that the light traverses per unit time. Note that this isn’t the same as your answer to (b) because the light bounces back and forth rather than following a straight path along the fiber.

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