An electric stove burner has surface area 325 cm² and emissivity e = 1. The burner consumes 1500 W and is at 900 K. If room temperature is 300 K, what fraction of the burner's heat loss is from radiation?

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An electric stove burner has surface area 325 cm² and emissivity e = 1. The
burner consumes 1500 W and is at 900 K. If room temperature is 300 K, what
fraction of the burner's heat loss is from radiation?
Transcribed Image Text:An electric stove burner has surface area 325 cm² and emissivity e = 1. The burner consumes 1500 W and is at 900 K. If room temperature is 300 K, what fraction of the burner's heat loss is from radiation?
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