An average of 10 jobs per hour arrives at a job shop. Interarrival times of jobs are exponentially distributed. It takes an average of 10/3 minutes to complete a job. Unfortunately, 1/3 of all completed jobs need to be reworked. Thus, with probability 1/3, a completed job must wait in line to be reworked. In steady state, how many jobs would one expect to find in the shop? What would the answer be if it took an average of 5 minutes to finish a job?
An average of 10 jobs per hour arrives at a job shop. Interarrival times of jobs are exponentially distributed. It takes an average of 10/3 minutes to complete a job. Unfortunately, 1/3 of all completed jobs need to be reworked. Thus, with probability 1/3, a completed job must wait in line to be reworked. In steady state, how many jobs would one expect to find in the shop? What would the answer be if it took an average of 5 minutes to finish a job?
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter5: Exponential And Logarithmic Functions
Section5.2: Applications Of Exponential Functions
Problem 44E: Use a graphing calculator to solve each problem. In Example 4, suppose that a birth control program...
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An average of 10 jobs per hour arrives at a job shop.
Interarrival times of jobs are exponentially distributed. It takes
an average of 10/3 minutes to complete a job. Unfortunately,
1/3 of all completed jobs need to be reworked. Thus, with
probability 1/3, a completed job must wait in line to be
reworked. In steady state, how many jobs would one expect to
find in the shop? What would the answer be if it took an
average of 5 minutes to finish a job?
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