H Review I ConstantsAn air-conditioning unit is fastened to a roof that slopes atan angle of 0 = 33° above the horizontal (Figure 1). Itsweight is a force F on the air conditioner that is directedvertically downward. In order that the unit not crush theroof tiles, the component of the unit's weightperpendicular to the roof cannot exceed 425 N. (Onenewton, or 1 N, is the Sl unit of force. It is equal to0.2248 lb.) (a) What is the maximum allowed weight ofthe unit? (b) If the fasteners fail, the unit slidesL = 1.60 m along the roof before it comes to a haltagainst a ledge. How much work does the weight forcedo on the unit during its slide if the unit has the weightUse the relationship between the magnitude and direction of a vector and its components to solvefor the target variable in question (a).Express your answer with the appropriate units.> View Available Hint(s)?F =ValueUnitscalculated in part (a)? The work done by a force F on anobject that undergoes a displacement š is W = F.3.SubmitFigure< 1 of 1>Part FUse the definition of the scalar product to solve for the target variable in question (b).Express your answer with the appropriate units.> View Available Hint(s)HẢW =ValueUnitsSubmitPearsonCopyright © 2022 Pearson Education Inc. All rights reserved.| Terms of Use | Privacy Policy | Permissions | Contact UsstvAa80F3DD23&*2348WERY{PDGHJKCNноттandcommandoption....Vcの* OCB>

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Description: H Review I ConstantsAn air-conditioning unit is fastened to a roof that slopes atan angle of 0 = 33° above the horizontal (Figure 1). Itsweight is a force F on the air conditioner that is directedvertically downward. In order that the unit not crush

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An air-conditioning unit is fastened to a roof that slopes at an angle of 0 = 33° above the horizontal (Figure 1). Its weight is a force F on the air conditioner that is directed vertically downward. In order that the unit not crush the roof tiles, the component of the unit's weight perpendicular to the roof cannot exceed 425 N. (One newton, or 1 N, is the Sl unit of force. It is equal to 0.2248 lb.) (a) What is the maximum allowed weight of the unit? (b) If the fasteners fail, the unit slides L= 1.60 m along the roof before it comes to a halt against a ledge. How much work does the weight force do on the unit during its slide if the unit has the weight calculated in part (a)? The work done by a force on an object that undergoes a displacement 5 is W = F.5.

An air-conditioning unit is fastened to a roof that slopes at an angle of 0 = 33° above the horizontal (Figure 1). Its weight is a force F on the air conditioner that is directed vertically downward. In order that the unit not crush the roof tiles, the component of the unit's weight perpendicular to the roof cannot exceed 425 N. (One newton, or 1 N, is the Sl unit of force. It is equal to 0.2248 lb.) (a) What is the maximum allowed weight of the unit? (b) If the fasteners fail, the unit slides L= 1.60 m along the roof before it comes to a halt against a ledge. How much work does the weight force do on the unit during its slide if the unit has the weight calculated in part (a)? The work done by a force on an object that undergoes a displacement 5 is W = F.5.

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter6: Applications Of Newton’s Laws Of Motion

Section: Chapter Questions

Problem 8PQ: A rectangular block has a length that is five times its width and a height that is three times its...

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