ACTIVITY 1: Monohybrid cross in cornIn corn the allele for purple seed (P) is dominant and the allelefor yellow seed (p) is recessive.What is the genotype for true-breeding purple corn?true-breeding yellow corn?If true-breeding (homozygous) purple corm is crossed with true-breeding yellow corn,Use the Punnett square below to predict the results of the F1offspring (male gametes on top, female on left):What is the phenotype of the F,?What is the genotype of the F,?Use the Punnett square below to predict the results of the F,(male gametes on top, female on left)ProbabilityGenotypePhenotype ACTIVITY 2: Human geneticsWe will examine some human phenotypes that are controlled bya single gene. For each characteristic, you will determine yourphenotype, possible genotype(s), and the frequency of yourphenotype in the class.A. Tongue-rolling: a single gene with two alleles, R andr, determines a person's ability to roll their tongue intoa U shape. A person that cannot roll their tongue ishomozygous recessive (rr).What is your phenotype?What is your genotype(s)?What is the frequency of your phenotype? (show yourwork)B. Widow's peak: a single gene with two alleles, W andw. The dominant allele (W) results in a hairline thatforms a distinct point in the center of the forehead.What is your phenotype?What is your genotype(s)?What is the frequency of your phenotype? (show yourwork)

Name: ACTIVITY 1: Monohybrid cross in cornIn corn the allele for purple see
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Description: ACTIVITY 1: Monohybrid cross in cornIn corn the allele for purple seed (P) is dominant and the allelefor yellow seed (p) is recessive.What is the genotype for true-breeding purple corn?true-breeding yellow corn?If true-breeding (homozygous) purple c

Genotype of true breeding Purple Corn is PP. Phenotype of F1 generation is Purple, because purple…

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ACTIVITY 1: Monohybrid cross in corn In corn the allele for purple seed (P) is dominant and the allele for yellow seed (p) is recessive. What is the genotype for true-breeding purple corn? true-breeding yellow corn? If true-breeding (homozygous) purple corn is crossed with true- breeding yellow corn, Use the Punnett square below to predict the results of the F1 offspring (male gametes on top, female on left): What is the phenotype of the F,?_ What is the genotype of the F,? Use the Punnett square below to predict the results of the F, (male gametes on top, female on left) Probability Genotype Phenotype

ACTIVITY 1: Monohybrid cross in corn In corn the allele for purple seed (P) is dominant and the allele for yellow seed (p) is recessive. What is the genotype for true-breeding purple corn? true-breeding yellow corn? If true-breeding (homozygous) purple corn is crossed with true- breeding yellow corn, Use the Punnett square below to predict the results of the F1 offspring (male gametes on top, female on left): What is the phenotype of the F,?_ What is the genotype of the F,? Use the Punnett square below to predict the results of the F, (male gametes on top, female on left) Probability Genotype Phenotype

Biology: The Unity and Diversity of Life (MindTap Course List)

14th Edition

ISBN:9781305073951

Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Chapter14: Chromosomes And Human Inheritance

Section: Chapter Questions

Problem 3GP: Human females have two X chromosomes (XX); males have one X and one Y chromosome (XY). a. With...

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Activity E: Predicting the outcome of a dihybrid cross The resulting phenotypic ratios in the F₂ generation of a dihybrid cross (2 traits) can be quite different than those observed from a monohybrid cross, but the process is essentially the same. First, you list all possible gametes each parent and subsequent parents can produce. Second, you then assign the gametes to a Punnett square and fill it in. Finally, you count the progeny and determine the number of progeny in each phenotypic category. Remember, when determining the types of gametes possible, each gamete must have one member of each homologous pair of chromosomes. This means there needs to be one copy of every gene. For example, if you are considering a T gene (ability to taste PTC) and an F gene (let's say earwax texture- wet earwax is dominant and dry earwax is recessive), each gamete must have one allele for the T gene (either T or t) and one allele for the F gene (either For f).
Dihybrid Basics TT or Tt = tall tt = short GG or Gg = green gg = white 1.) A tall green pea plant (TTG9) is crossed with a tall green pea plant (TtGg) FOIL each parent’s genotypes: tall green pea plant (TTGg) short white pea plant (TtGg) How many of the 16 offspring are: tall & green tall & white short & green short & white
estion 2 of 15 Ⓒ Macmillan Learning > Match each phenotype description to its corresponding sex chromosome genotype in humans. XX with SRY on X phenotypically female but karyotype indicates presence of both sex chromosomes XY with SRY deleted phenotypically male but karyotype indicates presence of only X chromosomes hp XXXX phenotypically female with some abnormalities and overexpression of X chromosome genes Answer Bank A 0 XXY phenotypically male with sterility and hypogonadism € US ES ☐ Attempt 2 Apr 1 XYY phenotypically male with an increase in average stature 3:52 STAY
Activity 4 Identification of phenotype of known genotype The characteristic of the color of the red tomato fruit (R) is dominant over the characteristic of the yellow color (r) The characteristic of the color of white flowers (W) is dominant over the characteristic of the color of the yellow flowers (w), and the characteristic length of the stem of the plant (T) is dominant over the short characteristic (t) If a red fruit plant with yellow and long-stemmed flowers is crossed, with anotheryellow, white-flowered and short-stemmed plant, knowing that the dominant characteristic is pure. What is the phenotype of individuals of the resulting generation?
Direction: Answer the following problems: 1. Predict the phenotypic ratios of offspring when a homozygous white cow is crossed with a roan bull. Illustrate using a Punnett square. 2. Complete the Punnett square for a cross between a black chicken (BB) and a white chicken (WW). Give the phenotype of the offspring in the F1 generation. Кey BB – black ww- white F1 BW – checkered Phenotype:
Drosohpila Punnet Square of Crosses. I need results of F1 & F2 generation using Punnett Squares for: Make Punnet Squares of the following crosses •Drosophila Female wildtype cross Male White-eye •Drosophila Male wildtype cross Female White-eye •Drosophila Female Wild Type cross Male Scarlet Eye •Drosophila Male Wild Type cross Female Scarlet Eye Also, Which allele is heterozygous and which is homozygous, & which is dominant and which is recessive?
Test Crosses: Determining Unknown Genotypes 3. Coat color in Labradors is caused by two different alleles of a color gene. The dominant allele, B, generates black fur, while the recessive allele, b, generates brown fur. Your neighbor has a black Labrador and is interested in understanding how to determine if his dog is homozygous or heterozygous for the black coat color genotype. Answer the following questions to determine how a test cross could help your neighbor discover his dog's genotype. a. What are the possible genotypes of your neighbor's Labrador? b. In a test cross, why is the organism of unknown genotype crossed to a homozygous recessive individual? Assign the possible paternal gametes of the unknown Labrador to the vertical axis in each of the Punnett squares at right. Assign the gametes of the homozygous recessive dog to the horizontal axes in each of the Punnett squares. c. What are the expected genotypes and phenotypes of the puppies that will result from the test cross…
(Purple) (White) 12. Two plants, both heterozygous for the gene that controls flower color are crossed. Give the expected RATIOS for each genotype and phenotype. Phenotype Ratio - Gentoype Ratio - 13. In guinea pigs, the allele for short hair is dominant over long hair. Two short haired guinea pigs are mated several times. Out of 100 offspring, 25 of them have long hair. What are the probable genotypes of the parents? (Show the cross to prove it!)
The second parental (P2)cross using a Punnett square Male Female Gg gg G GG Gg Because the P1 and P2 crosses consider the inheritance of only one character, seed color, they are called monohybrid crosses. Activity 3. SELF- CHECK 1. Windows peak (S) is dominant over straight hairline (s). Given that the mother has heterozygous gene pair for window's peak and the father has straight hairline. a. What is the genotype of the mother? b. What is the genotype of the father? C. How many kinds of gametes can the mother produce? List them down. d. How many kinds of gametes can the father produce? List them down. e. Perform a cross using a Punnett square. f. Give the genotypic ratio of the cross g. Give the phenotypic ratio of the cross
9 The color of Andalusian chickens results from the inheritance of alleles that exhibit incomplete dominance. Black Andalusian chickens result when two alleles for melanin production are inherited (MM). White-splashed chickens result from the inheritance of two copies of a different allele (mm). The heterozygous condition (Mm) results in their famous bluish color. Predict the genotypes and phenotypes from the following crosses: MM X mm and Mm x Mm. a. genotype of male b. genotype of female c. genotypes of offspring d. phenotypes of offspring e. genotype of male f. genotype of female g. genotypes of offspring h. phenotypes of offspring
O e. Parent 2: Parent 1: Parent 2: ¡Ai QUESTION 9 Bi QUESTION 8 Let's assume that, in dragons, red scales (B) are dominant to green scales (b), and long tongues (S) are dominant to short tongues (s). The genes that determine these characteristics assort independently. A homozygous red, long-tongued dragon is crossed with a homozygous green, short-tongued dragon. If an F1 dragon is crossed to a homozygous green and homozygous short-tongued dragon, what phenotypes and proportions are expected in the offspring? O a. 100% green and long-tongued O b. ½ green and short-tongued & ½ red and long-tongued O c. ½ red and short-tongued & ½ green and long-tongued O d.% red and long-tongued, % red and short-tongued, ½ green and long-tongued, % green and short-tongued O e. 9/16 red, long-tongued, 3/16 green, long-tongued, 3/16 red, short-tongued, 1/16 green, short-tongued Save and Submit to save and submit. Click Save All Answers to save all answers. 000 MacBook Air
Direction: Read and understand the ff. set of monohybrid cross problems and answer each problem by showing the Punnett square, genotypes ans phenotypes. 2. Horniess (H) in cattle is dominant over horned (h). A homozygous hornless bull is mated with a homozygous horned cow. What will be the genotype and phenotype of the first generation?