Abs vs Time Trial 1 Ln(Abs) vs Time Trial 1 1/Abs vs Time Trial 1 0.35 0.00 9.00 20 40 60 80 100 120 140 160 180 8.00 y= 0.0297x + 2.4624 R=0.989 0.3 y=-0.0012x + 0.3231 -a.s0 7.00 R= 0.9771 0.25 y=0.0059x - 1.0624 6.00 0.2 -1.00 R0.9993 5.00 0.15 4.00 . .. -1.50 3.00 0.1 2.00 0.05 -2.00 1.00 0.00 20 40 60 80 100 120 140 160 180 -2.50 20 40 60 80 100 120 140 160 180
Abs vs Time Trial 1 Ln(Abs) vs Time Trial 1 1/Abs vs Time Trial 1 0.35 0.00 9.00 20 40 60 80 100 120 140 160 180 8.00 y= 0.0297x + 2.4624 R=0.989 0.3 y=-0.0012x + 0.3231 -a.s0 7.00 R= 0.9771 0.25 y=0.0059x - 1.0624 6.00 0.2 -1.00 R0.9993 5.00 0.15 4.00 . .. -1.50 3.00 0.1 2.00 0.05 -2.00 1.00 0.00 20 40 60 80 100 120 140 160 180 -2.50 20 40 60 80 100 120 140 160 180
Chemistry for Engineering Students
3rd Edition
ISBN:9781285199023
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter11: Chemical Kinetics
Section: Chapter Questions
Problem 11.4PAE: What are the steps in the Chapman cycle? Explain the importance.
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I need help finding the rate law for each graph. The first graph is in order zero, the middle is in order first and the last is in order second.
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