A. Suppose TCP operates over a 1-Gbps link. Assuming TCP could utilize the full bandwidth continuously, how long would it take the sequence numbers to wrap around completely? В. fill in the blanks 1. The packets exchanged between TCP peers are called 2. In TCP Header The Acknowledgment, SequenceNum, and AdvertisedWindow fields are all involved in TCP's 3. In TCP Header The SYN flag is used when 4. Required window size for 100-ms RTT and bandwidth 1.5Mbps is 5. In Karn/ Partridge algorithm If the variance among Sample RTTS is small Then the Estimated There is no need to 6. АТM (-- 7. Instead of using coax cable, an Ethernet can be constructed from a thinner cable known as 10Base2, thus 10 means Base means 2 means that a

A. Suppose TCP operates over a 1-Gbps link. Assuming TCP could utilize the full bandwidth continuously, how long would it take the sequence numbers to wrap around completely? В. fill in the blanks 1. The packets exchanged between TCP peers are called 2. In TCP Header The Acknowledgment, SequenceNum, and AdvertisedWindow fields are all involved in TCP's 3. In TCP Header The SYN flag is used when 4. Required window size for 100-ms RTT and bandwidth 1.5Mbps is 5. In Karn/ Partridge algorithm If the variance among Sample RTTS is small Then the Estimated There is no need to 6. АТM (-- 7. Instead of using coax cable, an Ethernet can be constructed from a thinner cable known as 10Base2, thus 10 means Base means 2 means that a

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Please solve it correctly and please provide explanation of your answers. A PC and a Web Server are communicating over a TCP connection. The PC had started the three way handshake with the initial sequence number of 3069 . The Web Server's initial sequence number is 4830 . The window size of the PC is 815 bytes and the window size of the Web Server is 463 bytes. Using the third TCP handshake ack segment the PC sends the http request of the size 396 bytes to the Web Server. Then the Web Server answers with 3 segments containing the requested data. The first segment size is 42 bytes and the second segment size is 276 bytes and the third segment size is 146 bytes respectively. The PC receives all three segments within the timer. But unfortunately the second segment was corrupted. So the PC immediately sends an acknowledgement segment. Assume that the PC uses Selective Repeat/Reject ARQ. (d) What will be the window size of PC A after receiving only the first segment from webserver? (e)…
3.5-2 TCP segment format. For the given function of a field in the TCP segment, select the name of that field from the pull-down list.
Q1.Suppose a client, say C, has established a TCP connection with a server, say S. After establishing the connection, the sender sends two TCP messages with data back-to-back ( the first TCP message with sequence number 32 and the second TCP message with sequence number 100). a. What is the sequence number chosen by the client? What could be the reason for choosing this value of sequence number?b. What is the data size of first and second TCP data messages?c. Suppose the server receives the first and second TCP messages with data with the difference of 100 milliseconds delay. What could be the ACK number for both the TCP data messages from the server side as per the TCP RFC.
Please solve it correctly and please provide explanation of your answers. A PC and a Web Server are communicating over a TCP connection. The PC had started the three way handshake with the initial sequence number of 3069 . The Web Server's initial sequence number is 4830 . The window size of the PC is 815 bytes and the window size of the Web Server is 463 bytes. Using the third TCP handshake ack segment the PC sends the http request of the size 396 bytes to the Web Server. Then the Web Server answers with 3 segments containing the requested data. The first segment size is 42 bytes and the second segment size is 276 bytes and the third segment size is 146 bytes respectively. The PC receives all three segments within the timer. But unfortunately the second segment was corrupted. So the PC immediately sends an acknowledgement segment. Assume that the PC uses Selective Repeat/Reject ARQ. (a) What will be the sequence number of the third TCP handshake signal send from PC to webserver?…
Please solve it correctly and please provide explanation of your answers. Please answer parts g, h and i. A PC and a Web Server are communicating over a TCP connection. The PC had started the three way handshake with the initial sequence number of 3069 . The Web Server's initial sequence number is 4830 . The window size of the PC is 815 bytes and the window size of the Web Server is 463 bytes. Using the third TCP handshake ack segment the PC sends the http request of the size 396 bytes to the Web Server. Then the Web Server answers with 3 segments containing the requested data. The first segment size is 42 bytes and the second segment size is 276 bytes and the third segment size is 146 bytes respectively. The PC receives all three segments within the timer. But unfortunately the second segment was corrupted. So the PC immediately sends an acknowledgement segment. Assume that the PC uses Selective Repeat/Reject ARQ. g) The second segment from webserver was corrupted. So the PC…
5. Expand the information on the Transmission Control Protocol for this packet in the Wireshark “Details of selected packet” window (see Figure 3 in the lab writeup) so you can see the fields in the TCP segment carrying the HTTP message. What is the destination port number (the number following “Dest Port:” for the TCP segment containing the HTTP request) to which this HTTP request is being sent?
1. Suppose a TCP connection is transferring a file of 5550 bytes. The first byte is numbered 10001. What are the sequence numbers for each segment if each carries 500 bytes? How many Segments will be there ?
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9.Correct expression tor UDP user datagram length is length of UDP = length of IP- length of IP header's length of UDP= length of UDP-length of UDP header's length of UDP = length of IP+length of IP header's length of UDP = length of UDP+length of UDP header's.
* Question Completion Status: A Moving to the next question prevents changes to this answer. Question 6 Let the maximum TCP segment size be 3 KB. Assume also that the sender uses TCP Vegas for congestion control. The following parameters were recorded at the time of transmission # k: congestion window - 9 KB; round-trip time = 0.04 sec minimum (congestion-free) round-trip time - 0.01 sec a= 200 KB/sec; and B- 500 KB/sec. What will be the value of the new congestion window (in KB) at the time of transmission # k + 1? Write the value with no units. A Moving to the next question prevents changes to this answer. 1080 • acer
Assume a TCP sender sends four packets of size 1024 bytes, carrying bytes 0-4095. If the second packet is lost, what is the content of the Acknowledgement field sent in response to the third packet? (If you think that no acknowledgement is sent, for example because the third packet is out of order, then answer -1.)
For NAT Network Address Translation Scenario: Jenny Bello is a small business owner selling and making customized computer peripherals. She has been finding it difficult to track her sales and inventories, however recently after an expert's advice, she adopted a Point of Sale (PoS) server. So, she can now track her sales and inventories at the store. However, she ran into another issue, the server can only be accessed within the store, because it has been assigned a private IPv4 address, it is not publicly accessible via the Internet. a) Why is not having the PoS server accessible over the Internet a problem for the business? b) What caused this problem? c) Propose a solution for the problem and explain how the solution works.