a. Choose a chemical equation showing how the following species can behave as indicated when dissolved in water: HCO3 as an acid. ○ HCO3¯¯ (aq) + H₂O(1) ⇒ CO3² (aq) + H3O+ (aq) ○ HCO3¯¯(aq) + H₂O(1) ⇒ CO3² (aq) + H+ (aq) OHCO3¯¯(aq) + H₂O(1) ⇒ CO3¯(aq) + H+ (aq) O HCO3(aq) + H₂O(1) ⇒ H₂CO3(aq) + OH¯(aq) b. Choose a chemical equation showing how the following species can behave as indicated when dissolved in water: 2- CO3²- as a base. 2- CO3²- (aq) + H₂O(1) ⇒ H₂CO3(aq) + OH¯ (aq) CO3² (aq) + H₂O(1) ⇒ HCO3¯(aq) + OH¯(aq) CO3²- (aq) + H₂O(1) ⇒ H₂CO3(aq) + H+ (aq) O CO32- (aq) + H₂O(1) ⇒ HCO3¯(aq) + H+ (aq) c. Choose a chemical equation showing how the following species can behave as indicated when dissolved in water: HN₂O₂ as an acid. ○ HN₂O₂¯(aq) + H₂O(1) ⇒ H₂N2O₂ (aq) + OH¯(aq) ○HN₂O₂¯(aq) + H₂O(1) ⇒ H₂N2O2 (aq) + H3O+ (aq) ○ HN₂O₂¯¯ (aq) + H₂O(1) ⇒ N₂O₂² (aq) + H+ (aq) ○ HN₂O₂¯(aq) + H₂O(1) ⇒ N₂O₂² (aq) + H3O+ (aq)

Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter3: Chemical Reactions
Section3.6: Acids And Bases
Problem 3.5CYU
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a. Choose a chemical equation showing how the following species can behave as indicated when dissolved in water:
HCO3 as an acid.
HCO3(aq) + H₂O(1) ⇒ CO3² (aq) + H3O+ (aq)
HCO3(aq) + H₂O(1) ⇒ CO3² (aq) + H+ (aq)
HCO3¯(aq) + H₂O(1) ⇒ CO3¯(aq) + H+ (aq)
HCO3(aq) + H₂O(1) ⇒ H₂CO3(aq) + OH¯(aq)
b. Choose a chemical equation showing how the following species can behave as indicated when dissolved in water:
2-
CO3²- as a base.
CO3²- (aq) + H₂O(1) ⇒ H₂CO3(aq) + OH¯ (aq)
2-
CO3²- (aq) + H₂O(1) ⇒ HCO3¯(aq) + OH¯(aq)
O CO32 (aq) + H₂O(1) H₂CO3(aq) + H+ (aq)
2-
CO3²- (aq) + H₂O(1) ⇒ HCO3¯(aq) + H+ (aq)
c. Choose a chemical equation showing how the following species can behave as indicated when dissolved in water:
HN₂O₂ as an acid.
HN₂O₂¯¯ (aq) + H₂O(1) ⇒ H₂N2O₂ (aq) + OH¯(aq)
HN₂O₂¯(aq) + H₂O(1) ⇒ H₂N2 O2 (aq) + H3O+ (aq)
HN₂O₂ (aq) + H₂O(1) ⇒ N₂O₂² (aq) + H+ (aq)
HN₂O₂¯(aq) + H₂O(1) ⇒ N₂O₂² (aq) + H3O+ (aq)
2-
2-
Transcribed Image Text:a. Choose a chemical equation showing how the following species can behave as indicated when dissolved in water: HCO3 as an acid. HCO3(aq) + H₂O(1) ⇒ CO3² (aq) + H3O+ (aq) HCO3(aq) + H₂O(1) ⇒ CO3² (aq) + H+ (aq) HCO3¯(aq) + H₂O(1) ⇒ CO3¯(aq) + H+ (aq) HCO3(aq) + H₂O(1) ⇒ H₂CO3(aq) + OH¯(aq) b. Choose a chemical equation showing how the following species can behave as indicated when dissolved in water: 2- CO3²- as a base. CO3²- (aq) + H₂O(1) ⇒ H₂CO3(aq) + OH¯ (aq) 2- CO3²- (aq) + H₂O(1) ⇒ HCO3¯(aq) + OH¯(aq) O CO32 (aq) + H₂O(1) H₂CO3(aq) + H+ (aq) 2- CO3²- (aq) + H₂O(1) ⇒ HCO3¯(aq) + H+ (aq) c. Choose a chemical equation showing how the following species can behave as indicated when dissolved in water: HN₂O₂ as an acid. HN₂O₂¯¯ (aq) + H₂O(1) ⇒ H₂N2O₂ (aq) + OH¯(aq) HN₂O₂¯(aq) + H₂O(1) ⇒ H₂N2 O2 (aq) + H3O+ (aq) HN₂O₂ (aq) + H₂O(1) ⇒ N₂O₂² (aq) + H+ (aq) HN₂O₂¯(aq) + H₂O(1) ⇒ N₂O₂² (aq) + H3O+ (aq) 2- 2-
Expert Solution
Step 1

Bronsted-Lowry acid-base theory: The Bronsted-Lowry acid-base theory states that the acid is a substance that gives H+ ions and the base is a substance that accepts the H+ ions.

The species which are differing by the H+ are called conjugate acid-base pairs.

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