a) What is the value of your forecast? b) What if the weights were 0.40, 0.30, 0.20, and 0.10, respectively? Now what is the forecast for week 7? 083-849 c) Calculate the MAPE for both cases 202218
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- At the beginning of each week, a machine is in one of four conditions: 1 = excellent; 2 = good; 3 = average; 4 = bad. The weekly revenue earned by a machine in state 1, 2, 3, or 4 is 100, 90, 50, or 10, respectively. After observing the condition of the machine at the beginning of the week, the company has the option, for a cost of 200, of instantaneously replacing the machine with an excellent machine. The quality of the machine deteriorates over time, as shown in the file P10 41.xlsx. Four maintenance policies are under consideration: Policy 1: Never replace a machine. Policy 2: Immediately replace a bad machine. Policy 3: Immediately replace a bad or average machine. Policy 4: Immediately replace a bad, average, or good machine. Simulate each of these policies for 50 weeks (using at least 250 iterations each) to determine the policy that maximizes expected weekly profit. Assume that the machine at the beginning of week 1 is excellent.i need help with calculating rate of diffusion for 3 crystals and 6 crystals Diffusion Diffusion Diffusion Spot Spot Time Spot Diameter 1 Diameter 3 Diameter 6 (min) Crystal Crystals Crystals (mm) (mm) (mm) 10 15 0-15 0-15 20 16 0-16 0-16 30 18 0-18 0-18 Time Rate of Diffusion for Rate of Diffusion for 3 Crystals Rate of Diffusion for 6 Crystals (min) 1 Crystal (mm/hr) 0-10 90 0-20 48 0-30 36 (mm/hr) (mm/hr) Rate [mm/h] = (diameter [mm] / time [min]) x 60 [min] XChart and Regression analysis : What does the intercept predict? X: C16 (number of cars on the sales lot) versus Y: C17 (cars sold per day) Equation: y=2.9x + 14.5 Slope:2.9 Intercept:14.5 Does the intercept mean the intercept is 14.5 means that the cars sold per day( Y) predicted number of cars on sale lot(X) to be 14.5, but this intercept has no meaning. So, I will not use to predict cars sold per day?
- Study B: The decoy effect is the phenomenon that an additional but worse option can boost the appeal of an existing option. In order to get workers at food-processing factories in China to comply with hygiene standards (i.e., using hand sanitizer every hour), researchers manipulated whether there were additional options to the standard and convenient spray bottle provided to each employee. Workers in different rooms were randomly assigned to have just the standard spray bottle, or the standard spray bottle and an inconvenient squeeze bottle. Quality control personnel kept track of hand sanitizer use (weighing the bottles before and after each shift) and sanitary condition (sample wipes assessing the number of bacteria on hands). Neither the employees or quality control personnel were aware of the experiment or its hypothesis. The researchers found that when a decoy was present, workers used more sanitizer and were more likely to pass hand sanitary tests. In this example, it was…South Africa Airways would like to monitor its airline’s performance. Each week for the past 20 weeks, they checked each week a random sample of 100 flight arrivals for “one-time” performance. The table that follows contains the number of flights that did not meet South Africa Airways definition of “one time”: Week Late flights 1 2 2 4 3 10 4 4 5 1 6 1 7 13 8 9 9 11 10 0 11 3 12 4 13 2 14 2 15 8 16 2 17 3 18 7 19 3 20 2 Which control chart is appropriate to analyze the above data? Justify your answerSouth Africa Airways would like to monitor its airline’s performance. Each week for the past 20 weeks, they checked each week a random sample of 100 flight arrivals for “one-time” performance. The table that follows contains the number of flights that did not meet South Africa Airways definition of “one time”: Week Late flights 1 2 2 4 3 10 4 4 5 1 6 1 7 13 8 9 9 11 10 0 11 3 12 4 13 2 14 2 15 8 16 2 17 3 18 7 19 3 20 2 Calculate the upper and lower control limits for this chart.
- Bill Kime's bowling ball factory makes bowling balls of adult size and weight only. The standard deviation in the weight of a bowling ball produced at the factory is known to be 0.39 pounds. Each day for 24 days, the average weight, in pounds, of 9 of the bowling balls produced that day has been assessed as follows Day 1 2 3 4 5 6 Average (lb) 9.9 9.9 10.1 10.1 99 99 Day 7 8 9 10 11 12 Average (lb) Day Average (b) 13 14 15 16 17 18 10.1 10.0 10.0 10.1 10.1 10.0 9.9 10.1 10.1 10.0 10.1 10.1 Day 19 20 21 22 23 24 Average (lb) 99 10.0 10.1 9.9 10.0 10.0 a) Establish a control chart for monitoring the average weights of the bowling balls in which the upper and lower control limits are each two standard deviations from the mean What are the values of the control limits? Upper Control Limit (UCL)=b (Round your response to two decimal places)Describe how you would randomise observations and why it is important that the service user is unable to predict when you will observe them.Volumetric Glassware: Utility and Calibration (Dry Lab) Table B1: Calculation of a 100-mL Volumetric Flask. temperature of the Distilled H2O (°C) 27 density of distilled H2O at calibration temperature mass (g) of volumetric flask + distilled H₂O Trial 1 198.5893 Trial 2 198.6114 Trial 3 mass (g) of dry volumetric flask 98.6563 98.7503 198.6001 98.7145 mass (g) of distilled H₂O m true g calculated volume of water dispensed, cm³ corrected volume, V20 °c, cm³ average corrected volume, V20 °C, cm³ standard deviation (4 sig figs) %RSD (2 sig figs)