Question 1a) We write that, the electric field reigning in between the plates of a parallelplate capacitor, is constant. Why? Hint: Show, via using Gauss Law that auniformly charge infinite plane of surface density ơ, creates at any altitudeabove or below it, an electric field intensity E= o/2ɛ0, written n MKS unitsystem.b) Despite this result, the electric field intensity between the plates of a capacitoramounts to E= o/ɛ0 Why? Is the outcome valid near the edges of the plates?

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a) We write that, the electric field reigning in between the plates of a parallel plate capacitor, is constant. Why? Hint: Show, via using Gauss Law that a uniformly charge infinite plane of surface density o, creates at any altitude above or below it, an electric field intensity E= o/2ɛ0, written n MKS unit system. b) Despite this result, the electric field intensity between the plates of a capacitor amounts to E= 0/ɛ0 Why? Is the outcome valid near the edges of the plates?

a) We write that, the electric field reigning in between the plates of a parallel plate capacitor, is constant. Why? Hint: Show, via using Gauss Law that a uniformly charge infinite plane of surface density o, creates at any altitude above or below it, an electric field intensity E= o/2ɛ0, written n MKS unit system. b) Despite this result, the electric field intensity between the plates of a capacitor amounts to E= 0/ɛ0 Why? Is the outcome valid near the edges of the plates?

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter5: Electric Charges And Fields

Section: Chapter Questions

Problem 85P: Two thin parallel conducting plates are placed 2.0 cm apart. Each plate is 2.0 cm on a side; one...

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Question 1 a) Prove that, the electric field reigning in between the plates of a parallel plate capacitor, is constant. Hint: Show, via using Gauss Law that a uniformly charged infinite plane of surface density o, creates at any altitude above or below it, an electric field intensity E= a/2eo, written n MKS unit system. b) Despite this result, the electric field intensity between the plates of a capacitor amounts to E= alɛo Why? Is the outcome valid near the edges of the plates? c) The width between the plates is d. The electric potential between them amounts to, V=Ed. Why? d) Suppose the surface area of each plate is S, and the intensity of the stored charge is q. Show that the capacitance C=q/V, can be expressed as C=Sedd. e) The MKS unit for C'nin is Farad (Coulomb/Volt). Suppose C=Ix10-1² Farad, and V=1Volt. How many electrons under the given circumstnaces are moved form one plate to the other? The electron charge intensity is e=1.6x10-19 Coulomb.
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