A system has four processes and five allocatable resources. The current allocation and maximum needs are as follows: Allocated Махітит Available Process A 10211 11213 00x11 Process B 20110 22210 Process C 11010 21310 Process D 11110 11221
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- There are 3 resources R1, R2 and R3 with one instance each and three processes P1, P2 and P3 in an operating system. A snapshot of the system resource allocation graph shows the following: R1 is allocated to P2; R2 is allocated to P1; R3 is allocated to P3; P1 requests R1; P2 requests R3; P3 requests R2. Which of the following is true about this system? answer ) a)Undetermined b)There is deadlock in the system c)Deadlock will never happen d)There is no deadlock in the system81. Given a priori information about the ________ number of resources of each type that maybe requested for each process, it is possible to construct an algorithm that ensures that the system will never enter a deadlock state. a. minimum b. average c. maximum d. approximateA system has three processes (P1, P2, P3) and three reusable resources (R1, R2, R3). There is one instance of R1, two instances of R2 and three instances of R3. P1 holds an R1 and an R3 and is requesting an R2. P2 holds an R3 and is requesting an R1 and an R2. P3 holds two R2 and an R3 and is requesting an R1. How many cycles are there? Does a deadlokc exist? Why?
- An operating system comprises three user processes, and each of these processes consumes two units of the resource R. The minimal number of R units that must be employed in order to avoid deadlocks isThree user processes make up an operating system, and each of these processes uses a total of two units of the resource R. The bare minimum number of R units that must be employed to avoid any deadlocks isThree periodic processes of an operating system has P(burst time, period) as follows: P1(4,20), P2(6,10), P3(12,30). Which of the following is true when these processes are scheduled with Rate-Monotonic scheduling algorithm that assigns priorities proportional to periods (shorter period has higher priority). a)No process misses a deadline b)Only P3 misses its deadline c)P1, P2 and P3 all miss their deadlines d)P2 and P3 both miss their deadlines
- Three processes of an operating system has P(arrival time, burst time) as follows: P1(0,6),P2(2,5), P3(4,2). Work out the average waiting time in this system when processes are scheduled with Shortest-Remaining-Time-First scheduling algorithm. a)1.3 b)3 c)4 d) 2.5 Note : please with explain Oprating systemAn Operating System Resource Allocation Graph G shows processes and needed resources. Which graph condition proves that deadlock cannot occur? Which proves that deadlock is possible? Which condition is proof of deadlock?An operating system has three user processes, each of which uses two units of resource R. The smallest number of R units required to ensure that no deadlocks occur is
- Determine what is the type of decision mode (non-preemptive or preemptive) to be exercised on a process during uniprocessor scheduling under the following circumstances: a. A process is aborted. Interrupt take place based on a certain clock interval. A process is requesting for I/O. A new process arrival. A process is requesting for operating system services.Consider a computer system with 3 processes and one resource with 4 instances. Each process needs at most 2 resource instances. Is a deadlock possible in this system? Justify your answer.An operating system contains 3 user processes each requiring 2 units of resource R .The minimum number of units of R such that no deadlocks will ever arise is