A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. Solution a) Let us first derive the expression for the tension. By Newton's First Law ZF = the components of force that makes this so is EF = T = 0 Simplifying this results to 8/ (4) Analyzing the figure above, we arrive at (4) = sqrt( By substitution, we arrive at the following: T= + 2 Og/( sqrt ( 24 If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T- 0.370 N

A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. Solution a) Let us first derive the expression for the tension. By Newton's First Law ZF = the components of force that makes this so is EF = T = 0 Simplifying this results to 8/ (4) Analyzing the figure above, we arrive at (4) = sqrt( By substitution, we arrive at the following: T= + 2 Og/( sqrt ( 24 If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T- 0.370 N

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter14: Static Equilibrium, Elasticity, And Fracture

Section: Chapter Questions

Problem 85PQ

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Problem A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. L r m Solution a) Let us first derive the expression for the tension. By Newton's First Law ΣF 0 the components of force that makes this so is ΣFT cosphi mg = 0 Simplifying this results to T= m g/ cos Analyzing the figure above, we arrive at (4) = sqrt( L 2 + 2Lr %3D cos + | By substitution, we arrive at the following: T= m ( d + 2 L )g/( 2 sqrt ( L 2 + 2Lr If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T= 47 0.370 N
A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. a) Let us first derive the expression for the tension. By Newton's First Law ΣF = the components of force that makes this so is ΣF = T - = 0 Simplifying this results to T = g/(ϕ) Analyzing the figure above, we arrive at (ϕ) = sqrt( 2 + ) / ( / + ) By substitution, we arrive at the following: T = ( + 2 ) g / ( sqrt ( 2 + ) ) If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T = 0.370 N
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Problem A solid uniform ball with massm and diameter dis supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. L d Solution a) Let us first derive the expression for the tension. By Newton's First Law ΣF the components of force that makes this so is EF = T = 0 Simplifying this results to T= (4) Analyzing the figure above, we arrive at (4) = sqt 2+ By substitution, we arrive at the following: T= +2 sqrt ( )) If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T = 0.370 N
Problem A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. d m Solution a) Let us first derive the expression for the tension. By Newton's First Law ΣF the components of force that makes this so is ΣF - T = 0 Simplifying this results to T = g/ (4) Analyzing the figure above, we arrive at (4) = sqrt( + By substitution, we arrive at the following: 2 T = + 2 )g/( sqrt ( )) If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T = 0.370 N
Problem A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. r Solution a) Let us first derive the expression for the tension. By Newton's First Law
A ring of radius of 30cm and mass 10kg is pointed at a point A perpendicular to a wall find the the magnitude if force so that the ring will be in equilibrium. Take g as 10m/s². please answer qucikly
Problem A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. d Solution a) Let us first derive the expression for the tension. By Newton's First Law EF = the components of force that makes this so is EF = T = 0 Simplifying this results to T = g/ (4) Analyzing the figure above, we arrive at (4) = sqrt( 2. By substitution, we arrive at the following: T = sgrt ( 2+ )) If the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T = 0.370 N
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A solid uniform ball with mass m and diameter d is supported against a vertical frictionless wall by a thin massless wire of length L. a) Find the tension in the wire. L d r