A series RL circuit connected across a dc source through a SPST switch, three (3) milliseconds after the switch is closed, the voltage across the inductor is 20V and drops to 5V after 20 ms. if R = 100 ohms, find the value of L. Assume that t=0, i =0 A 1.30H B) 1.22 H c) 1.59H D) 1.25H LYSIAN MARKET Opremsbyjisoo mag dm: NIOUE MARКЕТ
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- Calibri (Body) -11 by AaBbCcDx AaBbCcD AaBbC AaBbCc AaB AaBbCc. mat Painter BIU 1Normal 1No Spaci. Heading 1 Heading 2 Title Subtitle Chang Styles d Font Paragraph Styles IMPEDANCE QUIZ # 2 1. What capacitance when connected in series with a 500Q resistor will limit the current drawn from a 48-mV 465-kHz source to 20µA? * a. 144pF b. 145pF c. 146pF d. 147pF MY ANSWER: c.146pF 2. What is the total impedance at 20kHz of a series circuit consisting of a 1.5mH inductance, a 100Q resistance, and a 0.08uF capacitance? * a. 1340 41.7 b. 1930 L-37.2" C. 920 290 d. 530 2-12.6°What's the rise time for this system with its closed-loop poles as shown? 14 -6 -4 12 -j6 Select one: a. 0.607 sec b. 3.14 sec C. 1.80 sec d. 0.254 seC e. 0.554 secIdentify which measurement this oscilloscope time difference reading is useful for. Oscilloscope-XSC1 Time 250.000 us 1.261 ms Channel_A 169.064 V 168.513 V -550. 584 mV Channel_B 89. 282 V 95.005 V 5.722 V Reverse T2-T1 1.011 ms Save Ext. trigger Timebase Scale: 200 us/Div : Scale: 100 V/Div X pos. (Div): 0 Channel A Channel B Scale: 100 V/Div Y pos. (Div): 0 Trigger Edge: F Level: 0 A B Ext Y pos. (Div): 0 V Y/T Add B/A A/B AC DC AC DC Single Normal O period O none of the above O phase shift
- A resistor R and a capacitor C are connected in series across a 400 V variable ac supply. When the frequency is 40 Hz, it draws 10 A current, and when the frequency is 50 Hz, it draws 15 A current. Find R and C.Q6) The waveform of the voltage obtained after rectification is of a -----nature and therefore contains .harmonics a. Sinusoidal O b. Triangular c. Pulsating O d. Repetitive OWhich methods can be used to estimate or calculate the maximum power point on an I-V curve?
- Adpole having anomentp=3-5ŷ +lont nc m is located at Q(ir3)-4jinfveespa.ce Find uet pase)I am getting the output of the clamper circuit wrong, how will this circuit be output ? circuit question : Set the input voltage signal to a sinusoid with 100 Hz frequency and 20V peak-to-peak amplitude with C=1μF. Obtain and plot the input and output voltage waveforms.An RC series circuit is connected to a 120-V, 60-Hz power source. The resistor is 25 and has a voltage drop of 65 volts. What is the capacitance of the capacitor?
- Identify which measurement this oscilloscope time difference reading is useful for. Ociloscope-XSC1 Channel_A 169.064 V 168.513 V Channel_B 89.282 V 95.005 V Time Reverse 250.000 us 1.261 ms 1.011 ms T2 T2-T1 -550. 584 mV 5.722 V Save Ext. trigger Channel A Timebase Scale: ko0 us/Div X pos. (Div): 0 Y/T Add B/A A/B Channel B Trigger Scale: 100 V/Div Y pos. (Div): 0 AC0 DC 100 V/Div f 2 AB Ext Scale: Edge: | Y pos.(Div): 0 AC 0 DC Level: V Single Normal Auto NoneA pure sinusoidal current is being rectified. For the given maximum value of half wave rectified current is 50 A, then the rms value of full wave rectification will be 50 (a) A (b) 100 - A TC (c) 100 A (d)70.7 AA clipper is a device that removes either the positive half (top half) or negative half (bottom half), or both positive and negative halves of the input AC signal. In other words, a clipper is a device that limits the positive amplitude or negative amplitude or both positive and negative amplitudes of the input AC signal. In some cases, a clipper removes a small portion of the positive half cycle or negative half cycle or both positive and negative half cycles. In the below circuit diagram, the positive half cycles are removed by using the series positive clipper. QUESTION: In your own opinion. Why do we need to clip a certain amount of voltage in positive or negative or on both sides? What is the benefit of that in our devices or circuits in doing such thing?