A sample soil is obtained and sieve analysis is performed to determined its particle distribution. Sieve Opening Mass Retained % Finer # 6 3.35 146 # 8 2.36 88 #16 1.18 125 # 40 0.425 56 #50 0.3 42 #140 0.106 127 # 200 0.075 126 Pan 29 Determine: 1. Effective Size (in mm and in 4 decimal places) 2. Uniformity Coefficient (in 2 decimal places) 3. Coefficient of Curvature (in 2 decimal places)

A sample soil is obtained and sieve analysis is performed to determined its particle distribution. Sieve Opening Mass Retained % Finer # 6 3.35 146 # 8 2.36 88 #16 1.18 125 # 40 0.425 56 #50 0.3 42 #140 0.106 127 # 200 0.075 126 Pan 29 Determine: 1. Effective Size (in mm and in 4 decimal places) 2. Uniformity Coefficient (in 2 decimal places) 3. Coefficient of Curvature (in 2 decimal places)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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In the dry sieve analysis of soil the sieves are placed as sequential order one below the other as: 75 mm, 63 mm,37.5 mm,28 mm, 20 mm, 14 mm, 10 mm, 6.3 mm, 4.75mm, 2.36mm, 1.18mm, 600µ, 300µ,150µ,75µ, pan Select one: O True O False
The Name :- Answer the following questions :-( Choose 5 only) 1- .is the moisture content that defines where the soil changes from a plastic to a viscous fluid state. 2- The difference between the PL and the LL is defined as.... 3- Why is it not possible to use core cutter method for calculating the density of cohesion less soil? 4- The relative density of a soil is 5- In the sieve analysis test Place the sieve stack in the mechanical shaker and shake for . minutes . 6- Hydrometer testing is performed on soil passing from a sieve.
7. Find the grain-size (gradation) distribution of the following: a. Original dry mass of sample 600 g b. The sample was then washed and graded. The weigh retained in each sieve is provided below. i. Retained in No. 16 (1.18 mm) ii. Retained in No. 100 (150 μm) iii. Retained in No. 200 (75 μm) iv. Retained in Pan 305.3 g 127.9g 76.4g 3.8g c. How would you classify this aggregate? Please select one from the list below and justify your answer a.- Open graded b.- Well graded c.- Gap graded
For a soil specimen, the following are given: % passing Sieve No. 4 = 92% % passing Sieve No. 10 = 81% % passing Sieve No. 40 = 78% % passing Sieve No. 200 = 65% LL = 48% PI = 32% Classify the soil by the AASHTO system. O A-2-7 (15) O A-7-6 (18) O A-7-6 (32) O A-2-5 (6)
The results of the particle-size analysis of the soil are as follows: Percent passing No. 10 sieve = 100; Percent passing No. 40 sieve = 80; Percent passing No. 10 sieve = 58.The LL and PI of minus No. 40 fraction of the soil are 30 and 10 respectively. Classify the soil by USCS system a. CH b. SP-SC c. CL-ML d. CL-ML
In the dry sieve analysis of soil the sieves 10 are placed as sequential order one below the other as: eutme 75 mm, 63 mm,37.5 mm,28 mm, 20 mm, 1dy af 14 mm, 10 mm, 6.3 mm, 4.75mm, 2.36mm, 1.18mm, 600µ, 300p,150µ,75µ, pan nere Select one: True False
dys.mu MSKÜ-LMS 016 ŞB: 1 ÖRGÜN Soil Mechanics Mühendislik Fakültesi Mac Atterberg limits of a soil sample are given: LL:55% and PL:25%. Give the name of the soil typle considering the chart given below? Remember PI=LL-PL 60 U-line PI - 0.9 (LL -8) 50 Z 40 CH or OH A-line PI0.73 (LL - 20) 30 CL OH 20 or OL MH CL- ML 10 ML& OL 10 20 30 40 50 60 70 80 90 100 Liquid limit (%) O a. CL or OL O b. CH OR OH O c. OH or ML O d. GL or ML O e. M ail E AR .ill lenovo Plasticity index (%)
type, d) QA. (5 Marks) Sieve analysis test on 400 gm of sand was conducted with the fo lowing records; Sieve No. 8 14 28 35 70 100 200 pan 2.362 1.168 0.589 0.417 0.295 0.147 0.074 Diameter (mm) Mass retained (gm) 60 100 72 48 62 18 30 A 60 160 B 280 342 360 390 C Total Retained (gm) % finer 85 60 42 30 D 10 2.5 a. What of the values of A, B, C and D. b. Determine the grading characteristics of this soil. c. Classify this soil according to its gradation using USCS method
no Sieve analysis test on 400 gm of sand was conducted with the following records; Sieve No. 8 14 28 35 70 100 200 pan 2.362 1.168 0.589 0.417 0.295 0.147 0.074 M Diameter (mm) Mass retained (gm) 60 100 72 48 62 18 30 A 60 160 B 280 342 360 390 Total Retained (gm) % finer 85 60 42 30 D 10 2.5 a. What of the values of A, B, C and D. b. Determine the grading characteristics of this soil. c. Classify this soil according to its gradation using USCS method. C
The soil tested at the laboratory was found that the particle passing sieve No.200 is 89%, retained on sieve No. 4 is 3%, Liquid limit of 70%, organic matter of 25%, and Plasticity Index of 40%. Determine the type of soil * PLASTICITY CHART 60 50 CH A LINE: Pl 0,73(LL-20)| 30 CL MH&OH 20 CL ML ML&OL 10 20 30 40 50 60 70 80 90 100 LIQUID LIMIT (LL) (%) O Organic clay O Clay with high plasticity O Organic Silt O Sandy Clay PLASTICITY INDEX (PI) (%)
The figure and the table below, shows the results of consolidation test for a soil sample, Find the cc value. TI Applied pressure, kPa 25 50 100 200 400 800 Voids ratio 0.634 0.619 0.583 0.523 0456 0383 0.65 0.6 0.55 0.5 0.45 0.4 of 0.35 10 100 1000 PRESSURE 0.15 0.21 0.12 no one 0.30 VOIDS RATIO
• Problem 2--- From the following data of the grain size analysis Sieve size #4 #8 #10 #25 #60 #100 # 200 Pan Sieve opening (mm) 4.76 2.36 2.00 0.71 0.25 0.149 0.074 Determine; a) Cu and Cc system % Finer (by weight) 80 56 51 35 18 13 7 ——— b) classify the soil using the unified soil classification