A ray is incident upon a reflective surface at an angle of θi=28.2∘relative to the direction normal to the surface (see image below to help visualize the situation). What is the angle of the reflected ray (θr) relative to the normal direction (in degrees)?
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A ray is incident upon a reflective surface at an angle of θi=28.2∘relative to the direction normal to the surface (see image below to help visualize the situation). What is the angle of the reflected ray (θr) relative to the normal direction (in degrees)?
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- A ray is incident upon a reflective surface at an angle of 0;=36.4° relative to the direction normal to the surface (see image below to help visualize the situation). What is the angle of the reflected ray (0,) relative the normal direction (in degrees)? Normal to surface Incident ray Reflected ray O; = 0,A ray of light strikes the midpoint of one face of an equiangular (60°-60°-60°) glass prism (n = 1.5) at an angle of incidence of 41.8°. (a) Trace the path of the light ray through the glass, and find the angles of incidence and refraction at each surface. First surface: incidence Recheck.the.problem statement to find the angle of incidence. ° refraction US Enter a number. Ofind the angle of refraction from the angle of incidence. ° Second surface: incidence Orefraction = (b) If a small fraction of light is also reflected at each surface, find the angles of reflection at the surfaces. (first surface) reflection = ° (second surface) reflectionA light ray traveling in air is incident on one face of a right-angle prism of index of refraction n=1.5 as shown in Fig., and the ray follows the path shown in the figure. Assuming 0 = 55° and the base of the prism is mirrored, determine the angle p made by the outgoing ray with the normal to the right face of the prism. Incoming ray Ourgoing ray 90° -0 Mirror base Select one: O A. 3.09 В. 32° O C. 12.7° D. 19.87° O E. 7.9°
- A ray is incident upon a reflective surface at an angle of θi=46.8∘ relative to the direction normal to the surface (see image below to help visualize the situation). What is the angle of the reflected ray (θr) relative to the normal direction (in degrees)?Ray 1 of light in medium a (see (Figure 1)) strikes the surface at 51.0∘ with respect to the normal. Take n1 = 1.35 and n2 = 1.65. (a)Find the angle of refraction of ray 1 with respect to the normal in medium b (in degrees). (b) Now repeat the problem with the light ray’s direction reversed. The ray now approaches from below at the angle that you calculated in Part A. Find the angle of refraction in medium a.(a) A narrow beam of light is incident on the left side of the prism shown in the figure below. The prism is a right triangle, with two of its angles measuring 45°. The transmitted beam that exits the hypotenuse of the prism makes an angle of 8 = 22.2° with the direction of the incident beam. What is the index of refraction of the prism? (Round your answer to at least two decimal places.) 7 45.0° Ⓡ (b) What If? In part (a), we assumed the beam was monochromatic. Consider instead the case where the beam was composed of white light. Because the index of refraction differs for different wavelengths, the white light would be dispersed into constituent colors. Assume the index of refraction for blue wavelengths is 1.01n and for red wavelengths it is 0.99n, where n is the index of refraction found in part (a). What is the angular spread (in degrees) between red and blue light exiting the prism?
- A ray of light crosses the boundary between some substance with n = 1.6 and air, going from the substance into air. If the angle of incidence is 29 what is the angle of refraction? Calculate to 1decimal.Suppose a ray comes from a point (2, 8) and hits at mirror point (6, 6). Assume that perpendicular vector a point (6, 6) is ?̅= (0, 3). Find the reflection emitting point from (6, 6).Using the direction of the reflected ray formula.When a light ray crosses from water into glass, it emerges at an angle of 30° with respect to the normal of the interface. What is its angle of incidence? I used Snell's Law to find the angle of incidence as 34.8 degrees (rounded to 3 sig fig), using index of refraction for water as 1.333 and for glass as 1.52. However, the answer was marked as wrong. Could you please explain steps for solving to get theta as approximately 42 degrees?
- A ray of light is incident upon a plane with an angle of (3.60x10^1)° relative to a line perpendicular to its surface (called the normal). What is its angle of reflection (in deg) relative to the surface? Note: Your answer is assumed to be reduced to the highest power possible.In the figure shown, a light ray travelling through air (n=1.0) strikes the surface of an unknown material. The soeed of light in this unknown material is only 1.2E8 m)s, and the angke marked (alpha) in the figure is 30 degrees. A) What is the index of refraction of the unknown material? B) What is the angle marked (Beta) in the figure? 2) Draw a history graph for the position x= -2m for the same wave pulse shown in the diagram figure above. Show some mathematical proofsA thick piece of Lucite (n = 1.50) has the shape of a quarter circle of radius R = 12.8 cm as shown in the side view of the figure below. A light ray traveling in air parallel to the base of the Lucite is incident at a distance h = 6.60 cm above the base and emerges out of the Lucite at an angle e with the horizontal. Determine the value of 8. Incoming ray Outgoing ray R