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A: Firing angle of the projectile (θ)=30o
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A: GivenInitial velocity of projectile ,u=320 m/sAngle ,θ =15°Time ,t=10 s
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A: Range of projectile is u2sin2θg maximum height of the projectile is u2sin2θ2g
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Q: A projectile is fired with an initial velocity of 320m/s at an angle of 15o with the horizontal.…
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Q: A projectile is fired with an initial velocity of 320m/s at an angle of 15 deg with the horizontal.…
A: Given value--- Initial velocity = 320 m/s. angle = 15 degree . We have to find--- horizontal…
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Q: A person standing on the roof of a building 20 m above the ground kicks a ball horizontally from the…
A: Height of the building (h) = 20 m Horizontal speed of the ball (u) = 10 ms
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A: Given: The intial speed of the projectile is 125 m/s. The angle of the projection is 45o.
Q: A projectile is fired at an angle of 45° with the horizontal with a speed of 500 m/s. Find the…
A: Given data: Initial velocity (v0) = 500 m/s Angle (θ) = 45°, with the horizontal Required: The…
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A: Required : Path of a projectile in the absence of air resistance.
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A: muzzle velocity = Vo= 50.86 cm per second Angle = 30° So horizontal component of velocity, is Vxo…
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A: Initial velocity of projectile (v) = 50 m/s Launch angle (θ) = 30o
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A: Let the projectile is launched at an angle of θ with the velocity v0.
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A: Given data: Angle, θ=60o Launch speed, vo=5 m/s
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A: (given) v0=150 m/sx=980 m (Horizontal distance) y=400 m (vertical distance)s=x2+y2 =(980)2+(400)2…
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A: Given: Initial velocity=v0=60mph=602.237=26.8224 ms Angle of projection=θ=15°
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A: a)The equation for vertical displacement is given by
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- A ball is thrown at an initial height of 100 feet at an initial velocity of 80 feet/second at an angle of 45 degrees. Given the parametric equations y = 16t + Vo sin(0) · t + ho and r Vo cos(0)t. - When doing calculations, carry 5 digits of accuracy, so your round off does not build up. a. What is the ball's height in 1 seconds? feet. b. When will the object hit the ground? seconds. c. How far horizontally will the ball be when it hits the ground? feet. d. When will the ball be at its maximum height? seconds. e. What is the ball's maximum height? feet. feet f. How far horizontally will the ball be when it reaches its maximum height?You toss a ball from your hand, at height, yi, at an initial speed of 10.00 m/s, at an angle of 30.0∘ above the horizontal. The ball travels for 2.0 seconds before landing on the ground. Ignore air resistance in this problem. 1. Please sketch a picture of the problem 2. List all the known valuesYou fire a ball with an initial speed V0 at an angle (ϕ) above the surface of an incline, which is itself inclined at an angle (θ) above the horizontal (Figure below). a. Find the distance, measured along the incline, from the launch point to the point when the ball strikes the incline. b. What angle ϕ gives the maximum range, measured along the incline? Ignore air resistance. c. Since there's no air resistance, this is a problem in projectile motion. The goal is to find the point where the ball's parabolic trajectory intersects the incline. It is best to choose the x-axis to be horizontal and direct to the right, the y-axis to be vertical and direct to the up, and the origin to be at the point where the ball is fired. In the projectile equations, the launch angle α0 is measured from the horizontal. What is this angle in terms of (θ) and (ϕ)?
- A prankster flips a coin off of the Empire Building at a height of 1054 feet above the ground. The initial vertical velocity of the coin is 1.20m/s. In real life, air resistance would limit the maximum speed the coin can attain during its fall, but if air resistance were not a factor and assuming it has practically no horizontal motion, answer the following questions. (1 foot = 0.3048m) a. What would the coin's velocity be when it hits the ground? b. How long would it take to hit? c. How high would the coin be halfway through the total falling time, and how fast would it be falling then?(a) A daredevil is attempting to jump his motorcycle over a line of buses parked end to end by driving up a 32° ramp at a speed of 40.0 m/s (144 km/h). How many buses can he clear if the top of the takeoff ramp is at the same height as the bus tops and the buses are 20.0 m long? (b) Discuss what your answer implies about the margin of error in this act—that is, consider how much greater the range is than the horizontal distance he must travel to miss the end of the last bus. (Neglect air resistance.)Part 5 of 8 - Analyze The students must use their trial shot to find the muzzle speed. They need a plan. Read their discussion and decide who has the best plan. Cameron: Let's set the launcher to 45°. We will then just measure the distance between the launcher and where the ball lands. This is the maximum range so we find the muzzle speed using the range equation. Avi: The angle doesn't matter. Just launch the ball at any angle. Time how long it takes to land, and measure the distance between the launcher and the place where it lands. The muzzle speed is just that distance divided by the time. In choosing between the two plans, consider the reasoning behind each statement below. Then select all the answers that have good reasoning and the correct plan. O Cameron has made a mistake. There is nothing special about launching the ball at 45°. Avi's plan is correct. |Cameron is correct. The range equation works for this trial shot because the ball lands at the same height as the launcher.…
- On a dare from a friend, you decide to try to jump a canyon using your bicycle as shown in the figure below. We will define a successful jump as one that allows you to just make it to the edge of the canyon on the far side. Ꮎ Yramp Calculate all the following: A custom ramp has been constructed for you which is yo = 29.6 meters high and is tipped an an angle of 0 = 44.7 degrees. The canyon has a width of Xcanyon 106.8 meters. Xcanyon The initial velocity, vo, of your bike? meters/second The time spent flying through the air second guessing your judgement? secondspeople love to play with balls nowadays especially during quarantine as theres not much to do. lets say we have a ball that hits another ball that is at the rest. after they hit and smash each other, the first ball moves 4m/s on the platform and makes an angle of 25 degrees while the other ball has a speed of 3m/s.. FIND a)get the angle b3tween da d1rection of motion of da second one (ball) and the original direction of motion of da first one. b) find da original sp33d of the first one c)let me ask u this question. is the kinetic energy is being conserving?I asked the question here before but the solution was wrong. that's why I will ask again. Sam and William are playing with a ball. Sam throws the ball 30 s after William started to run away from the starting position. If William is accelerating 1.6 m/s2 starting from rest, find the initial velocity of the ball to hit the moving target and the ground at the same time. The ball is thrown 1.5 m from the ground and 46° from the horizontal. Choices: a. 112 m/s b. 126 m/s c. 163 m/s d. 143 m/s
- A physics book slides off a horizontal tabletop with a speed of 5 cm/s. It strikes the floor in 0.250 s. Ignore air resistance. Find, a.) the height of tabletop above the floor. b.) the horizontal distance from the edge of the table to the point where the book strikes the floor. c.) the horizontal and vertical components of the book's velocity, and the magnitude and direction of its velocity, just before the book reaches the floor.Hi, can anyone help me with this scenario? I'm very confused and now stuck on the questions. On the apollo 14 mission to the moon, astronaut Alan Shepard hit a golf club improvised from a tool. The free-fall acceleration on the moon is 1/6 of its value on earth. Suppose he hit the ball with a speed of 25 m/s at an angle 26 degrees above the horizontal. A.) How long was the ball in flight? B.).How far did it travel? C.) Ignoring air resistance, how much farther would it travel on the moon than on the earth? Thank you for all your help!A crazy person jumped off a 100-meter cliff because of climate change. He is launched up in the air at a velocity of 20m/s in a direction making an angle of 250 upward with the horizontal. a.) What is the maximum height reached by the crazy person? b.) What is the total time flight (between launch and touching the ground) of the crazy person? c.) What is the horizontal range of the crazy person? d.) What is the magnitude of the velocity of the crazy person just before it hits the ground?
