A novel compound named “sanaoline” with a partition coefficient (KD) of 6 was extracted from 5.0 grams of Lagundi leaves which contains 0.8% of the compound. How much of sanaoline in milligrams remains in 100.0 mL of the aqueous phase if 5 successive extractions using 50. mL of petroleum ether?
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A novel compound named “sanaoline” with a partition coefficient (KD) of 6 was extracted from 5.0 grams of Lagundi leaves which contains 0.8% of the compound. How much of sanaoline in milligrams remains in 100.0 mL of the aqueous phase if 5 successive extractions using 50. mL of petroleum ether?
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- 1,4‐Dimethoxybenzene (0.642 g) was dissolved in 2.0 mL acetic acid in a 25 mL Erlenmeyer flask using heat from a hot plate. Once the solid dissolved, 1.0 mL tert‐ butanol was added, and the reaction mixture was cooled in an ice bath. Then 2.0 mL concentrated sulfuric acid was added in 2‐3 drop portions,stirring the mixture after each aliquot. After the addition, the flask was removed from the ice bath and allowed to sit at room temperature for 15 minutes. Then 1.0 mL water was added dropwise to dilute the acid and the reaction mixture was added to 40 mL cold water in a 100 mL beaker. The solid was vacuum filtered and washed with 5 mL cold water, giving 52 g filtrate. The product wasrecrystallized from 4.5 mL methanol, yielding 0.317 g purified 1,4‐di‐tert‐butyl‐2,5‐dimethoxy benzene (27.2% yield). What is the atom economy, e-factor, and effective mass yield?please draw (in chemical structures) the balanced reaction of mixture of 0.3 grams of thiamine hydrochloride in 0.45 mL of water and 3.0 ml of 95 percent ethanol and then add 2 M NaOHA typical protein contains 16.2 wt% nitrogen. A 0.500-mL aliquot of protein solution was digested, and the liberated NH3 was distilled into 10.00 mL of 0.021 40 M HCl. Unreacted HCl required 3.26 mL of 0.019 8 M NaOH for complete titration. Find the concentration of protein (mg protein/mL) in the original sample.
- Describe the preparation of 500 mL of 0.0750 M AgNO3 from the solid reagent.Hexanoic acid was added to an immiscible biphasic solvent system, water and CCl4 at 20.0OC and the equilibrium concentrations of hexanoic acid were determined to be 3.66 g/L in H2O and 67.0 g/L in CCl4. Caluclate the distrubution coeffiecent (D2) of hexanoic acid in water with respect to CCl4.12 g of compound “Y” dissolves in 10 ml of acetone at 25 oC and 0.85 g of the same compound dissolves in 10 ml of boiling acetone. What volume of acetone would be required to purify a 5.0 g sample of compound?
- The sample is dissolved in a mixture containing 10ml of distilled water and 20 ml of dilute HCL.After dilution, add 50 ml of water and 1g of potassium bromide.The mixture is titrated with 0.1N NaNO2 solution . 4 drops of atropine are used as an indicator .At the last point of the titration the color change from red to yellow. Write the reaction that takes place in the nitrometer and the sulfatiazole sample indicator?Why a precipitate of manganese dioxide be removed from the potassium permaganate solution before standardization?2. If 6 g of phenol (weak acid, pKa 9.9) is distributed between 100 mL of an aqueous buffered solution at pH 5 and 150 mL of mineral oil, how much phenol is left in the mineral ail layer? The partition coefficient for phenol in this system is 2.3.
- The Kjedahl procedure was used to analyze 256 µL of a solution containing 37.9 mg protein/mL. The liberated NH3 was collected in 5.00 mL of 0.033 6 M HCl, and the remaining acid required 6.34 mL of 0.010 M NaOH for complete titration. What is the weight percent of nitrogen in the protein? wt%What is the minimum distribution constant that permits removal of 99% of a solute from 50.0 mL of water with five 10.0-mL extractions with toluene?The ethyl acetate concentration in an alcoholic solution was determined by diluting a 10.00-mL sample to 100.00 mL. A 20.00-mL portion of the diluted solution was refluxed with 40.00 mL of 0.04672 M KOH:CH3COOC2H5 + OH- → CH3COO- + C2H5OHAfter cooling, the excess OH2 was back-titrated with 3.41 mL of 0.05042 M H2SO4. Calculate theamount of ethyl acetate (88.11 g/mol) in the original sample in grams