A memory chip has 5 address lines and 6 bits per location/word. Derive the number of bits in this chip.
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A memory chip has 5 address lines and 6 bits per location/word. Derive the number of bits in this chip.
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- c) Given a 32K x 8 RAM chips. Compute: i) the number of chips needed to build a 128K byte memory using 32K x 8 RAM. ii) the number of address lines that must be used to access the memory. iii) the number of lines connected to the address inputs of each chip, the number of lines to be used for chip select inputs and type of decoder to be used. iv) Determine the range of addresses for the 128K byte memory.2. A microprocessor has a memory space of 4 MB. Each memory address occupies one byte. a) What is the address bus size (number of bits needed for addressing) of this microprocessor? b) What is the range (lowest to highest, in hexadecimal) of the memory space for this microprocessor? c) Complete the memory map by the address ranges (lowest to highest, in hexadecimal) 8 bits for each memory chip. 0x 0x 0x 0x 0x 0x 0x 0x Address 0 1MB 1MB 1MB 1MBGiven that a 16 bit data word (shown) is to be stored in memory, what is the correct sequence of bits, including the parity bits, to be stored, given that you are using Hamming code to achieve the goal? Assume an even parity system. 16-bit data word 0100100010000100 Hint: The solution has 21 bits in it!
- the diagram on the right is for a register bank circuit that contain 8 registers. Each register is 16-bit. Theregister can read or write to one register at a time using address bus.Design the circuit and specify the width of EVERY bus.Draw the figure for memory segments with 8086 microprocessor software model. Explain the logical address structure used for each segment (Explain which registers are used in logical address presentation of each segment; segment address : offset address). Give an example solution to find the physical address in a segment from the logical address for 8086 microprocessor.A common bus system which is capable of transferring 2 bits at time with number of registers are 4 each register is of 2 bit? Draw circuit diagram for this and also define how many multiplexers are required and what will be the size of multiplexer with truth table ?Also explain how to gather data from this bus back into register.
- A system with 16 bits address bus can access 2^16 memory space. Estimate the size of each memory IC that will require for a memory module if the number of bits required for the chip select is 87. What is the word length of an 8-bit microprocessor? a) 8-bits - 64 bits b) 4-bits - 32 bits c) 8-bits 16 bits d) 8-bits - 32 bits20. Suppose we have just found yet another representation for floating point numbers. Using this representation, a li2-bit floating point number has 1 bit for the sign of the number, 4 bits for the exponent and 7 bits for the mantissa, which is normalized as in the Simple Model so that the first digit to the right of the radix points must be a 1. Numbers in the exponent are in signed 2's complement representation. No bias is used and there are no implied bits. Show the representation for the smallest positive number this machine can represent using the following format (simply fill in the squares provided). What decimal number does this equate to? : SIGN EXPONENT MANTISSA
- 29) Write an assembly language program in 8086 microprocessor to find square root of a number. 30) Write an assembly language program in 8086 microprocessor to reverse 16 bit number using 8 bit operation. Assume 16 bit number is stored at memory location 2050 and 2051. 31) Write an assembly language program in 8086 microprocessor to divide a 16 bit number by an 8 bit number. Assumption – Initial value of each segment register is 00000. - Calculation of physical memory address – Memory Address = Segment Register * 10(H) + offset, %3D where Segment Register and Offset is decided on the basis of following table.Which of the following is incorrect? Select one or more: In AVR, the data memory includes 32 general registers, 64 I/O registers and SRAM. In AVR, both program and SRAM memories have 8-bit data width. The AVR can read both an instruction and data from memory at the same time. The more registers we have for a CPU, the slower processing we can.A memory location has a logical address where the segment address is 2019h and the offset address is the 0084h. Find the physical address of the memory location. please help me with those questions, those are from – Microprocessor and Interfacing, Electrical and electronics engineering.