A cat shows yellow (O) as a dominant color to orange (o) color. A heterozygous yellow-bodied male cat mates with an orange-female. What are the possible genotypes and phenotypes of the offspring that result from this mating? Including a Punnett Square.
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Question:
A cat shows yellow (O) as a dominant color to orange (o) color. A heterozygous yellow-bodied male cat mates with an orange-female.
What are the possible genotypes and
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- (This one is more complicated). Two true breeding fruit flies are allowed to mate. One fly ishomozygous dominant for body color and eye color while the other is homozygous recessive forbody color and eye color. (g+:gray body, g:black body, e+:ebony eyes, e:red), The F1 flies areallowed to mate. What are the following probabilities in the F2 generation? For this problemmake sure to show the Punnett Square for your F2 generation and all of your calculations. Youdo not need to show the Punnett Square for the F1 generation. Answer in percent and round to 2decimals.a. Two of three fruit flies are gray and red.b. The first fruit fly is gray and ebony, the second fruit fly is gray and red, and the third fruit fly is black and ebony.Coat color in mice is incompletely dominant. Yellow and white-colored mice are homozygous, while cream-colored mice are heterozygous. If two cream-colored mice mate, what phenotypic ratio can we expect of their offspring? Please show the solution.In dogs, a dominant gene (1) determines white coat, and a recessive gene (i) gives colored coat. In the presence of ii the coat color is black due to the dominant gene B, or brown due to the recessive gene b. Two dogs both having the Bbli genotype were mated. Answer the following questions and show complete solutions to support your answers. Use the branching method whenever applicable. What is the phenotypic ratio of the offspring? What type of gene interaction is exhibited by the coat color in dogs? What would be the probability of getting dogs that are pure-breeding for a black coat color? 3. a. b. C.
- Question 2 Consider the following gene on the "X" for color blindness: "XB" for normal vision is dominant to "Xb" for color blindness. Two individuals with the following genotypes mate: Female: XB Xb Male: XBY Answer the following questions using the information above: 1. What are the parental phenotypes? 2. What are the possible gametes each parent can produce? 3. What are the odds of having a child who is colorblind? 4. Among the female offspring (assuming they have a daughter), what are the chan of having a child with normal vision? BI Y V I E C D STT T HTML Editor X = 13 12pt Y ParagrPart 4: Answer each of the following questions. You must include a Punnett square to support each answer!! 18. In fruit flies, brown bodies (B) are dominant to black bodies (b) Cross a black fruit fly with a heterozygous fruit fly. Determine the phenotypic and genotypic ratios of their potential offspring. "B b Brown B Black B bb Name: Linda Rivas b Bb B/BB Bb 19. In humans, dimples (D) are dominant to no dimples (d). Cross a woman who is homozygous dominant with a man who is homozygous recessive. Determine the phenotypic and genotypic ratios of their potential offspring. Same Dd x dd dd:Dd: DD 2 2 O d Dd d Dd R Heredity Unit RR dd TTT tTt dd 20. In tomatoes, red fruit (R) is dominant to yellow fruit (r). Cross a homozygous dominant fruit with a heterozygous fruit. What percentage of their offspring will have yellow fruit? R RR x Rr Red Fruit RR Bb X bb Bb: bb: BB 2 1 f Ffff f Ff ff RR: Rrirr r Rr 2 2 21. In pea plants, tall plants are dominant to dwarf plants. Two heterozygous plants…in certain fish the mating of black-scaled (B) with white a white-scaled (W) will create offspring with a patchwork with black and white scales. which type of inheritence pattern is this?
- BLACK VESTIGIAL DIHYBRID TESTCROSS In the parental generation, you mate a pure-breeding wild-type female (bl+/blt.vg+/vg+) with a pure-breeding black, vestigial (bl/bl vg/vg) to produce an F1 generation that is all wild-type (bl+/bl vg+/vg). Note that the F1 flies are all dihybrid. Next, you mate several F1 dihybrid females (bl+/bl vg+/vg) with tester males, which are black, vestigial (bl/bl;vg/vg). The offspring of this dihybrid testcross are: Phenotype Genotype Tester Gamete Dihybrid Gamete Number 440 Wild-type 394 108 135 Black, vestigial Vestigial Black Copy the table into your notes and derive the dihybrid gametes following the example in the previous section. The columns in blue (phenotypes and numbers of offspring) are what you can see and count. The genotypes of the testcross offspring (orange) must be deduced from the phenotypes and knowing that the tester contributed bl vg gametes. Finally, you can deduce the dihybrid gametes (green) by subtracting the tester gamete…Choice 2: Black versus orange fur is determined by two alleles an X-linked gene (XⓇ, Xº), Suppose that a black male is mated with an orange female. a) Write the genotypes of the male and female cats. Male: Female: b) What genotypes & phenotypes are expected among the offspring (F1) of these parent cats? c) Suppose that a male and a female from part b mate. What offspring types will they produce?A fruit fly with a gray body and red eyes (genotype BbPp) is mated with a fly having a black and purple eyes (genotype bbpp). Show diagrammatically a genetic cross between the two flies and the possible genotypes and phenotypes of F1. What ratio of offspring would you expect if the body-colour and eye-colour genes are on different chromosome (unlinked)? When mating is actually carried out, most of the offspring look like the parents, but 3% have a gray body and purple eyes, and 3% have a black body and red eyes. Compare and discuss the observation with your answer in part (
- With regard to scurs in cattle ( a sex influenced trait) a cow with no scurs whose mother had scurs had offspring with a bull with scurs whose father had no scurs. What are their probabilities of having the following combinations?a. their first offspring will not have scursb. their first offspring will be a male with no scursc. their first three offspring will be females with no scurs step by step explain in details please!!!!Heterozygous Cp cp chickens express a condition called creeper, in which the leg and wing bones are shorter than normal (cp cp). The dominant Cp allele is lethal when homozygous. Two alleles of an independently segregating gene determine white (W-) versus yellow (ww) skin color. From matings between chickens heterozygous for both of these genes, what phenotypic classes will be represented among the viable progeny and what are their expected relative frequencies?In dogs, a dominant gene (I) determines white coat, and a recessive gene (i) gives colored coat. In the presence of ii the coat color is black due to the dominant gene B, or brown due to the recessive gene b. Two dogs both having the Bbli genotype were mated. Answer the following questions and show complete solutions to support your answers. Use the branching method whenever applicable.a. What is the phenotypic ratio of the offspring?b. What type of gene interaction is exhibited by the coat color in dogs?c. What would be the probability of getting dogs that are pure-breeding for a black coat color?