(a) Calculate the tension (in N) in a vertical strand of spiderweb if a spider of mass 5.00 x 10-5 kg hangs motionless on it. (Enter a number.) 0.00049 N (b) Calculate the tension (in N) in a horizontal strand of spiderweb if the same spider sits motionless in the middle of it much like the tightrope walker in the figure. 5.0° T₂ TR T. + W TR 5.0° ( ..The.strand sags at an angle of 14.0° below the horizontal. (Enter a number.) XN Enter a number. Compare this with the tension in the vertical strand (find their ratio). (Enter a number.) (tension in horizontal strand) / (tension in vertical strand) = X

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter5: Newton's Laws Of Motion
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the first part of the question is correct but i cant figure out the second part of the question.

(a) Calculate the tension (in N) in a vertical strand of spiderweb if a spider of mass 5.00 x 10-5 kg hangs motionless on it. (Enter a number.)
0.00049
✔ N
(b) Calculate the tension (in N) in a horizontal strand of spiderweb if the same spider sits motionless in the middle of it much like the tightrope walker in the figure.
5.0°
TR
T₁
W
TR
-5.0⁰
..The.strand sags at an angle of 14.0° below the horizontal. (Enter a number.)
XN
Enter a number.
Compare this with the tension in the vertical strand (find their ratio). (Enter a number.)
(tension in horizontal strand) / (tension in vertical strand) =
X
Transcribed Image Text:(a) Calculate the tension (in N) in a vertical strand of spiderweb if a spider of mass 5.00 x 10-5 kg hangs motionless on it. (Enter a number.) 0.00049 ✔ N (b) Calculate the tension (in N) in a horizontal strand of spiderweb if the same spider sits motionless in the middle of it much like the tightrope walker in the figure. 5.0° TR T₁ W TR -5.0⁰ ..The.strand sags at an angle of 14.0° below the horizontal. (Enter a number.) XN Enter a number. Compare this with the tension in the vertical strand (find their ratio). (Enter a number.) (tension in horizontal strand) / (tension in vertical strand) = X
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