A beam of monochromatic light is diffracted by a slit of width 0.620 mm. The diffraction pattern forms on a wall 1.30 m beyond the slit. The width of the central maximum is 1.80 mm. Calculate the wavelength of the light in nm. 1 nm = 10-⁹ m
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- A beam of monochromatic light is incident on a single slit of width 0.630 mm. A diffraction pattern forms on a wall 1.35 m beyond the slit. The distance between the positions of zero intensity on both sides of the central maximum is 2.10 mm. Calculate the wavelength of the light. .049 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. nmX rays of wavelength 0.0820 nm are scattered from the atoms of a crystal. The second-order maximum in the Bragg reflection occurs when the angle is 20.5°. (Figure 1) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of X-ray diffraction. Part A What is the spacing between adjacent atomic planes in the crystal? Express your answer in nanometers. ΓΙ ΑΣΦ d = Submit Previous Answers Request Answer ? nm1. O -12 points SerPSE9 38.P.001.MI.FB. My Notes O Ask Your Teacher Light of wavelength 588.0 nm illuminates a slit of width 0.80 mm. (a) At what distance from the slit should a screen be placed if the first minimum in the diffraction pattern is to be 0.89 mm from the central maximum? m (b) Calculate the width of the central maximum. mm Need Help? Read It Master It 2. O -11 points SerPSE9 38.P.005. My Notes + Ask Your Teacher Coherent microwaves of wavelength 5.00 cm enter a tall, narrow window in a building otherwise essentially opaque to the microwaves. If the window is 45.0 cm wide, what is the distance from the central maximum to the first-order minimum along a wall 6.50 m from the window? cm Need Help? Read It 3. -/1 points SerPSE9 38.P.007.MI.FB. My Notes Ask Your Teacher A screen is placed 60.0 cm from a single slit, which is illuminated with light of wavelength 690 nm. If the distance between the first and third minima in the diffraction pattern is 3.10 mm, what is the width of…
- What happens to the diffraction patters when the following are changed? Thoroughly describe each. a. The width of a single slit, w b. The width w and separation d of double slit c. The number of multiple slits N d. The distance from the slit plate to the sensor L e. The experimental y value collected from your data.There are two categories of ultraviolet light. Ultraviolet A (UVA) has a wavelength ranging from 320 nm to 400 nm. It is necessary for the production of vitamin D. UVB, with a wavelength in vacuum between 280 nm and 320 nm, is more dangerous because it is much more likely to cause skin cancer. Part A Find the frequency range of UVA. Enter the minimum and maximum values of the range. Enter your answers in hertz separated by a comma. 15| ΑΣΦ fmin, fmax = Submit Part B fmin. fmax = Submit Find the frequency range of UVB. Enter the minimum and maximum values of the range. Enter your answers in hertz separated by a comma. 195| ΑΣΦ Part C kmin, Kmax = Request Answer Part D Request Answer Submit Request Answer ? Kmin, kmax= What is the range of the wave numbers for UVA? Enter the minimum and maximum values of the range. Enter your answers in radians per meter separated by a comma. 17| ΑΣΦ ? Hz ? Hz ? What is the range of the wave numbers for UVB? Enter the minimum and maximum values of the…Use the worked example above to help you solve this problem. If the spacing between certain planes in a crystal of calcite (CaCO3) is 0.3 nm, find the grazing angles at which first- and third-order interference will occur for x-rays of wavelength 0.0692 nm. 0₁ 02
- In the figure, two radio-frequency point sources S1 and S2, separated by distance d = 2.4 m, are radiating in phase with A = 0.6 m. A detector moves in a large circular path around the two sources in a plane containing them. How many maxima does it detect? Number i UnitsThe thickness of a human hair was measured using diffraction. A green laser (λ = 532 nm) was used and the viewing screen was placed 1 m away from the slit plate. The table below shows the data gathered for m = ±1. Trial 2y (cm) 1 2.09 2 2.03 3 2.01 4 2.05 5 2.07 a. How is the wave nature of light demonstrated in the experiment? b. How do you calculate 0? Explain. C. How thick is the human hair strand used in the experiment?In a Young's double-slit experiment, 550-nm-wavelength light is sent through the slits. The intensity at an angle of 2.00⁰ from the central bright fringe is 84% of the maximum intensity on the screen. What is the spacing between the slits? 1.18e-6 x Your response differs from the correct answer by more than 10%. Double check your calculations. m
- Problem 2 For wavelengths in the visible spectrum, the index of refraction of a cer- tain type of crown glass can be approximated by the relation n(1) = 1.5255 + (4825 nm²)/a². b. Find the phase velocity, in this glass, for a pulse with frequency com- ponents centered around 500 nm. c. Find the group velocity, in this glass, for a pulse with frequency com- ponents centered around 500 nm.Which of the following best explains the reason for taking three measurements at each light intensity instead of a single measurement? Select one or more: a. By taking three measurements at each light intensity, the investigator could identify any result that was not expected and repeat the measurements until the expected result was obtained. b. By taking three measurements at each light intensity, the investigator could eliminate any result that did not support the hypothesis. c. By taking three measurements at each light intensity, the investigator could be more confident in the accuracy of the measurements than if the measurement had been made only once.c) Figure Q3 (c) shows the X-ray diffraction patterns of Aluminum powder by CuK- radiation. i. Sketch the (311) plane in cubic structure using miller indices solution. ii. Calculate the planar spacing, d hkl and angle, 0 hkl for (311) peak if the lattice constant, a is 0.404 nm and I is 0.1542 nm. Note that the diffraction condition is 2dhkl sin 0 = n]. iii. Determine whether the crystal structure of Aluminum powder belongs to bcc or fcc lattices. Justify your answer. (111) 100 A=0.1542 nm (CuK „-radiation) 80 60 (200) 40 (311) (220) 20 (222) (400) (331)(420) 20 30 40 50 60 70 80 90 100 110 120 20 (degrees) Fig. Q3 (c): X-ray diffraction pattern of Aluminum powder by CuK_- radiation. Inte nsity (arbitrary units)