A battery is connected in series to a capacitor and a resistor. At time = Os the capacitor is uncharged. After some amount of time later it is found that 2.5 Coulombs of charge have accumulated on the capacitor. What is the current going through the circuit at this instant in time? (Use the diagram below. Hint: Consider the loop rule) 2.5 Amps O 0.25 Amps 5 Amps 0.5 Amps t = 0 T 5 V t>0 C = 1 Farad -Q = 2.5 C R = 10 Ohm I = ?
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- You are an electrician working in an industrial plant. You discover that the problem with a certain machine is a defective capacitor. The capacitor is connected to a 240-volt AC circuit. The information on the capacitor reveals that it has a capacitance value of 10 mF and a voltage rating of 240 VAC. The only 10-mF AC capacitor in the storeroom is marked with a voltage rating of 350 WVDC. Can this capacitor be used to replace the defective capacitor? Explain your answer.Three capacitors having capacitance values of 20F,40F, and 50F are connected in parallel to a 60 - Hz power line. An ammeter indicates a circuit current of 8.6 amperes. How much current is flowing through the 40F capacitor?You are working in an industrial plant. You have been instructed to double the capacitance connected to a machine. The markings on the capacitor, however, are not visible. The capacitor is connected to 560 volts and an ammeter indicates a current of 6 amperes flowing to the capacitor. What size capacitor should be connected in parallel with the existing capacitor? What is the minimum AC voltage rating of the new capacitor? What is the minimum DC voltage rating of the new capacitor? What is the minimum KVAR size that can be used in this installation?
- You find that a 25-F capacitor connected to 480 VAC is defective. The storeroom has no capacitors with a 480-VAC rating. However, you find two capacitors rated at 50 F and 370 VAC. Can these two capacitors be connected in such a manner that they can replace the defective capacitor? If yes, explain how they are connected and why the capacitors will not be damaged by the lower voltage rating. If no, explain why they cannot be used without damaging the capacitor.A 15-F AC capacitor is connected in series with a 50 resistor. The capacitor has a voltage rating of 600 WVDC. The capacitor and resistor are connected to a 480-V, 60-Hz circuit. Is the voltage rating of the capacitor sufficient for this connection?An RC series circuit is connected to a 120-V, 60-Hz power source. The resistor is 25 and has a voltage drop of 65 volts. What is the capacitance of the capacitor?
- You are a journeyman electrician working in an industrial plant. Your task is to connect an inductor to a 480-V, 60-Hz line. To determine the proper conductor and fuse size for this installation, you need to know the amount of current the inductor will draw from the line. The nameplate on the inductor indicates that it has an inductance of 0.1 H. An ohmmeter reveals that it has a wire resistance of 10 . How much current should this inductor draw when connected to the line?Describe the behavior of the voltage across the resistor with time as thecapacitor charges. Explain the reason for this behavior.An alternating voltage is applied to a series circuit consisting of a resistor and iron-cored inductor and a capacitor. The current in the circuit is 0.5 A and the voltages measured are 30 V across the resistor, 48 V across the inductor, 60 V across the resistor and inductor and 90 V across the capacitor. Find (a) the combined copper and iron losses in the inductor (b) the applied voltage.
- An alternating voltage is applied to a series circuit consisting of a resistor and iron-cored inductor anda capacitor. The current in the circuit is 0.5 A and the voltages measured are 30 V across the resistor,48 V across the inductor, 60 V across the resistor and inductor and 90 V across the capacitor.Find (a) the combined copper and iron losses in the inductor (b) the applied voltage Answer: [(a) 3.3 W (b) 56 V]An alternating voltage is applied to a series circuit consisting of a resistor and iron-cored inductor anda capacitor. The current in the circuit is 0.5 A and the voltages measured are 30 V across the resistor,48 V across the inductor, 60 V across the resistor and inductor and 90 V across the capacitor.Find (a) the combined copper and iron losses in the inductor (b) the applied voltage.Answer: [(a) 3.3 W (b) 56 V] Note: Please provide a clear solution!In the diagram below, the switch S has been closed for a long time. A) What is the output voltage Vout? What is the charge on the capacitor? b) The switch is opened, so the output voltage increases. What is the time constant that describes the charging of the capacitor in terms of R and C? c) When Vout reaches 10 V, the switch closes and the capacitor begins to discharge. What is the time constant that describes the discharging in terms of R and C? Hint: Apply Kirchhoff's Rules to both loops and the sum of the currents at the junction above the capacitor in the diagram, and use I=dq/dt. If the switch opens when Vout reaches a lower value, say 5V, the capacitor will charge again, and thus one can cycle the voltage with a time constant determined by the circuit: this demonstrates the principle of operation of an electronic timer. 4R S 15 V Vout R