A ball is thrown straight down with an initial speed of 2.0 m/s from a height of 15 m. What is the position of the ball after 3.0 s, in meters? Use g = 9.8 m/s2. Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement

A ball is thrown straight down with an initial speed of 2.0 m/s from a height of 15 m. What is the position of the ball after 3.0 s, in meters? Use g = 9.8 m/s2. Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement

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Description: A ball is thrown straight down with an initial speed of 2.0 m/s from a height of 15 m. What is the position of the ball after 3.0 s, in meters? Use g = 9.8 m/s2.Your answer needs to have 2 significant figures, including the negative sign in your answ

Physics for Scientists and Engineers with Modern Physics

10th Edition

ISBN:9781337553292

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Vectors

Section: Chapter Questions

Problem 35AP: A person going for a walk follows the path shown in Figure P3.35. The total trip consists of four...

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My question isn't how to solve the problem exactly. In fact, it's already been solved on this website. My question is about the acceleration. When I solve this problem myself, first I calculate the velocity by dividing 100m by 53s. I get 1.89m/s. Then I use that to find the acceleration using the equation vf = vi + at. That's 1.89/53 = 0.036m/s^2. That's not correct. The correct way to find the acceleration is to us the equation d = 1/2 at^2 and solve that way without taking the intermediate step of finding the velocity. Doing it that way, the acceleration is 0.0712m/s^2. My question is why you get a different result doing it the first way than you get doing it the second way.
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