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The following data were obtained for the adsorption of acetone on charcoal from an
aqueous solution at 180C.
Y (millimoles/g) | C (millimoles/liter) |
0.208 | 2.34 |
0.618 | 14.65 |
1.075 | 41.03 |
1.5 | 88.62 |
2.08 | 177.69 |
2.88 | 268.97 |
a) Find the constants k and n of the Freundlich equation.
b) Find the constants a and b in the Langmuir equation.
c) Find the constants k and n in the Temkin isotherm.
d) Which of the isotherm fit the data best?
Answer letter D only thank you!
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- In an experiment on the adsorption of oxygen on tungsten it was found that the same volume of oxygen was desorbed in 27 min at 1856 K and 2.0 min at 1978 K. What is the activation energy of desorption? How long would it take for the same amount to desorb at (i) 298 K, (ii) 3000 K?In a study of the gas phase decomposition of hydrogen iodide at 700 K HI(g)V½ H2(g) + ½ I½(g) the concentration of HI was followed as a function of time. It was found that a graph of 1/[HI] versus time in seconds gave a straight line with a slope of 1.72×103 M1s1and a y-intercept of 0.667 M1. Based on this plot, the reaction is order in HI and the rate constant for the reaction is M1s1The following data were obtained for the adsorption of a certain material (ORA) on activated carbon at 25 °C. Sample number [ORA) initial (M) [ORA] at equilibrium Activated carbon mass (М) (g) 1.0119 0.0096 0.0044 2 1.0186 1.0360 0.0289 0.0578 0.0207 0.0446 3 4 1.0129 0.0867 0.0721 1.0393 1.0312 1.0198 1.0270 1.0252 0.1002 0.1156 0.1445 0.1270 0.1742 0.2227 7 0.1926 8 0.2407 0.2889 0.1108 4. If a monolayer of N2 molecules is 0.03075 mole per one gram of activated carbon, and the surface area on one N2 molecules is 0.162 nm, determine: a. surface area per one gram of activated carbon b. surface area of one ORA molecule
- The following data were obtained for the adsorption of a certain material (ORA) on activated carbon at 25 °C. Sample Activated carbon mass (g) 1.0119 [ORA) initial (M) [ORA] at equilibrium (М) 0.0044 number 0.0096 1.0186 1.0360 0.0289 0.0207 3 0.0578 0.0446 0.0721 0.1002 4 1.0129 0.0867 1.0393 0.1156 1.0312 1.0198 0.1445 0.1926 0.2407 0.2889 0.1270 7 1.0270 1.0252 0.1742 0.2227 0.1108 8 1. Try fitting these data using Langmuir Isotherm and obtain K and monolayer of ORA molecules per one gram 3. Which isotherm describe best the adsorption of ORA on activated carbon and why? 4. If a monolayer of N2 molecules is 0.03075 mole per one gram of activated carbon, and the surface area on one N2 molecules is 0.162 nm, determine: a. surface area per one gram of activated carbon b. surface area of one ORA moleculeIn a study of the gas phase decomposition of dinitrogen pentoxide at 335 K N2O5(g)2 NO2(g) + ½ O2(g) the concentration of N2O3 was followed as a function of time. It was found that a graph of In[N,05] versus time in seconds gave a straight line with a slope of -6.82×103 s and a y-intercept of -2.58 . Based on this plot, the reaction is first v order in N20z and the half life for the reaction is seconds.What is the difference between a diffusion reaction and a diffusion-controlled reaction?
- The following data were obtained for the adsorption of a certain material (ORA) on activated carbon at 25 °C. Sample number [ORA) initial (M) [ORA] at equilibrium Activated carbon mass (M) (g) 1.0119 0.0096 0.0044 1 2 1.0186 1.0360 0.0289 0.0578 0.0207 3 0.0446 4 1.0129 0.0867 0.0721 1.0393 1.0312 0.1002 0.1270 0.1742 0.1156 6. 0.1445 7 1.0198 0.1926 8 1.0270 1.0252 0.2407 0.2227 0.2889 0.1108 4. If a monolayer of N2 molecules is 0.03075 mole per one gram of activated carbon, and the surface area on one N2 molecules is 0.162 nm2, determine: a. surface area per one gram of activated carbon b. surface area of one ORA moleculeа. Identify THREE (3) isotherm shapes that are typically encountered in an adsorption process for a single adsorbate and illustrate the behavior through equilibrium relations.Iodine is sparingly soluble in water but much more so in carbon tetrachloride. The equilibrium constant, also called the partition coefficient, for the distribution of I2 between these two phases I2(aq) =12(CCI4) is 83 at 20°C. (a) A student adds 0.028 L of CCI4 to 0.213 L of an aqueous solution containing 0.037 g I2. The mixture is shaken and the two phases are then allowed to separate. Calculate the fraction of I2 remaining in the aqueous phase. 4.0 (b) The student now repeats the extraction of I2 with another 0.028 L of CCI4. Calculate the fraction of I2 from the original solution that remains in the aqueous phase. 4.0 (c) Compare the result in (b) with a single extraction using 0.056 L of CCI4. Comment on the difference. After a single extraction using 0.056 L of CCI4, the fraction of I2 that remains in the aqueous phase is 40 This result is larger than the result in (b), which means that a single large extraction is not as efficient as two separate smaller extractions.