A 6.00 g bullet is fired horizontally into a 1.20 kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.200. The bullet remains embedded in the block, which is observed to slide 0.230 m along the surface before stopping.
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- A particle of mass 2.5kg moves according to the equation x(t)-10t, where x is in meters and t is in seconds. The force (in N) acts on the particle is Select one: a. 25 b. 40 с. 35 d. 50Sam, whose mass is 74.0 kg, takes off across level snow on his jet-powered skis. The skis have a thrust of 220.0 N and a coefficient of kinetic friction wtih the snow of 0.07. Unfortunately, the skis run out of fuel after only 11.5 seconds. What Sam's top speed (in m/s) assuming that the acceleration due to gravity is 9.80 m/s2? How far (in m) has Sam traveled when he finally coasts to a stop?An object with a mass of 1.76 kg is initially at rest upon a horizontal, frictionless surface. An applied force of 3.04 N i acts on the object for 2.08 s. What is the object's final speed? Enter a number rounded to 2 decimal places and assume the answer has proper SI Units.
- A 663 kg hammer of a pile driver is lifted 3.3 meters above a piling head. If the hammer is released, what will be its velocity (in m/s) at the instant it strikes the piling?Correct Answer: 8.0 ± 0.1If you have a ball with a mass of 6.00kg, that has an initial velocity of vA=(2.00i + 5.00j)m/s and a final velocity of vB=(-2.00i + 8.00j)m/s, What is the change in velocity in unit vector format? a. -4.00i + 3.00j b. -2.83i + 3.61j c. 4.00i – 3.00j d. 0.00i + 13.0jV and V2 on a frictionless surface. They collide As shown in the figure below, two objects are moving towar ds each cther with velocities given by the vectors V3. If the masses m1 - 1.4 m2 what is the magnitude of V3 in m/s? perfectly inelastically and then move together as indicated ty the vector Provide your answer with 2 decimal places. e1 = 38.1 degree 62 = 11.6 degree = 9.4 m/s m1 m2 V 02 Va 3
- The horizontal distance to collision is 8242.96 m. The time of collision is 10.487 sec. What is A in m/s^2A 48.3 kg student runs down the sidewalk andjumps with a horizontal speed of 4.34 m/sonto a stationary skateboard. The studentand skateboard move down the sidewalk witha speed of 4.07 m/s. a) Find the mass of the skateboard.Answer in units of kg. I got 3.204177 kg b) How fast would the student have to jumpto have a final speed of 5.27 m/s?Answer in units of m/s. I'm getting 5.6196 m/s, but my online homework is prompting me with an incorrect guess. My work is shown in the picture.Position vector= r = (4t^2 +t^2)i + (3t^4 + t^2 + 8)j + (2t^2)k. Find velocity v acceleration a, P=momentum, Force=F?
- e 7.2××10-3 kg⋅m/skg⋅m/s. Express this quantity as provided or use any equivalent unit. (Note: 1 kgkg = 1000 gg).A 1.68 kg mass is initially at rest upon a frictionless, horizontal surface. An applied force of 9.13 N i then acts on the mass for 3.72 seconds. What is the speed of the mass when the applied force stops acting?Substituting, for the coefficient of kinetic friction, we find Xn = 0.25 3 6 m m +); 2 10 (2 451 N/m) ( 0.36 9 ) (25/ 06-6) (CM (ત્ર m m X ney Pi1991 fan of ap by ne anen f S OX