Bd 11. Need a b and c Car On RoupIngA 2750kg car isbraking while driving down a ramp,whose angle is 5 degrees plus the day ofthe month of your birth - if you wereborn on the 15", your ramp angle is20degrees.Assume the car tires are rolling, notsliding while braking, so use staticfriction coefficients throughout, and thecar's acceleration is nonzero. Alsoassume weight is distributed evenly overall four tires, which all provide the sameamount of friction as each other - 4 ofthe total.Use friction coefficients for rubber onconcrete from the table in Chapter 5 ofyour text, and for rubber on ice use theshoes on ice coefficient.A. What is your birthday of the month andthe ramp angle?B. Sketch this problem.C. Draw a complete and correct Free BodyDiagram for this problem. Label allforces.D. Write the equations of motion (N2x andN2y).E. Calculate the size and direction of allforces and their components in terms ofthe coefficient of static friction us.F. (Three cases) What is the maximumbraking deceleration the tires canprovide to the car before they startsliding if the road isDry? Wet??ley???

Since you have been posted multiple sub parts. So, we are solving only first three sub parts for…

A 2750kg car is braking while driving down a ramp, whose angle is 5 degrees plus the day of the month of your birth- if born on the 15", your ramp angle is 20degrees. Assume the car tires are rolling, not sliding while braking, so use static friction coefficients throughout, and the you were car's acceleration is nonzero. Also assume weight is distributed evenly over all four tires, which all provide the same amount of friction as each other - 4 of the total.

A 2750kg car is braking while driving down a ramp, whose angle is 5 degrees plus the day of the month of your birth- if born on the 15", your ramp angle is 20degrees. Assume the car tires are rolling, not sliding while braking, so use static friction coefficients throughout, and the you were car's acceleration is nonzero. Also assume weight is distributed evenly over all four tires, which all provide the same amount of friction as each other - 4 of the total.