A-2.50% grade meets a +1.75% grade at station 44+25 and elevation 3386.92 ft, 400-ft curve, stakeout at half stations. ▾ Part A ▾ Determine the elevation at the low point of the curve. Express your answer in feet to six significant figures. 195] ΑΣΦ. 11 Ivec Elev= Submit Part B Request Answer Determine the station at the low point of the curve. O 46+95.58 O 44+60.29 O 39+89.71 O 37+54.42 Submit Request Answer → C [C] ? ft

A-2.50% grade meets a +1.75% grade at station 44+25 and elevation 3386.92 ft, 400-ft curve, stakeout at half stations. ▾ Part A ▾ Determine the elevation at the low point of the curve. Express your answer in feet to six significant figures. 195] ΑΣΦ. 11 Ivec Elev= Submit Part B Request Answer Determine the station at the low point of the curve. O 46+95.58 O 44+60.29 O 39+89.71 O 37+54.42 Submit Request Answer → C [C] ? ft

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Item 1 A-2.5% grade meets a +2.50% grade at station 4 + 200 and elevation 146.657 m, 180-m curve, stakeout at 30-m increments. Part A List station elevations for an equal-tangent parabolic curve for the data given. Give the elevations in order of increasing X. Express your answers in meters to six significant figures separated by commas. Elev = Submit Provide Feedback OF V—| ΑΣΦ| | | vec Request Answer ? m
L-500 250 250 Figure 3 al Exam - Figure 3.pdf + Calculate the elevation of curve B at station 11+50. 115.90 117.94 118.80 119.80 120.80 29+ /2+50 Ind 13175
BALANCE THE TRAVERSE BY TRANSIT RULE AND COMPUTE THE AREA BY DMD METHOD Corr'n Corr'n Distance Line Bearing Latitude Departure Corrected Latitude DMD Corrected Departure Lat Dep Double deg min 1 2 s 23 37E 113.35 2 3 s 25 56 w 93.32 3 4 s 87 25 w 172.92 4 5 N 55 46 w 165.88 5 6 N 51 59E 184.89 6 1 s 85 51E 160 S() E (+) S(-) N(*) W(-) N (*) E (+) W() Area
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A-2.60% grade meets a +1.70% grade at station 44+25 and elevation 3387.96 ft, 400-ft curve, stakeout at half stations. Part A Tabulate station elevations for an equal-tangent parabolic curve for the data given above. Express your answers in feet to six significant figures separated by commas in order of increasing station numbers. Elev = Submit ΑΣΦ ↓↑ Request Answer vec ? ft
Q4/ Compute the reduce level of the points for the following readings, then draw the profile using scale (1:5000) for distances and (1:50) for the elevations, so draw the grade line starting from station (0+00) sloping (0.5 %) to down to station (5+00) and find the height of cut and fill ? Station 1 2 3 4 5 6 7 8 9 10 11 Dis. (m) 0+00 1.52 0+50 1+00 2.59 1+50 B.S. I.S. 2+00 1.12 2+50 3+00 1.16 3+50 4+00 1.22 4+50 5+00 1.91 1.92 1.44 1.82 2.30 F.S. 2.41 1.48 1.50 1.91 3.85 H.I. Ele. 25.00 Ele.of Height grade of cut Height of fill
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