8-10: In gerbils, the allele for long tail (7) is dominant to short tail (†). If two heterozygous parents produce offspring, what are the following probabilities? 8. The first offspring has a short tail? A) 0.0
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Introduction:
Law of Dominance states that dominant alleles always mask the recessive alleles. In heterozygous condition always dominant allele is expressed in F1 generation. The characters that appear in an F1 generation are called as dominant alleles and which are not expressed are recessive.
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- 1- In garden peas, yellow (Y) seed color is dominant to green (y). Because yellow and green are two different forms of the same gene (seed color), they are alleles. Use a Punnett square to show a cross between two heterozygous pea plants. What are the phenotype(s) of the offspring? What are the genotype(s) of the offspring? 2- In garden peas, yellow (Y) seed color is dominant to green (y). Because yellow and green are two different forms of the same gene (seed color), they are alleles. Use a Punnett square to show a cross between two heterozygous pea plants. What are the phenotype(s) of the offspring? What are the genotype(s) of the offspring? Use the information below to answer questions 3-6 There may be a number of possible alleles for a given gene within a population. In a multiple allele system the dominance relationships between the various alleles must be considered. One of the more familiar examples of a multiple allelic system is that of the human ABO blood group. The gene…9-10. In watermelons, the genes for green color and short shape are dominant over their alleles for striped color and for long shape. Suppose a plant with long striped fruit is crossed with a plant heterozygous for both of these characters. What phenotypes would this cross produce and in what ratios? Phenotypes = 1/2 short/green 1/2 long/green= 1:1 ratio Phenotypes = 1/4 short/green 1/4 short/striped 1/4 long/green 1/4 long/striped = 1:1:1:1 ratio Phenotypes = 3/4 short/green 1/4 long/green = 3:1 ratio Phenotypes = All short/green = 1:0 ratio15-16. In the fruit fly, vestigial (tiny) wings and hairy body are produced by recessive genes. The normal alleles, long wings and hairless body, are dominant. If a vestigial- winged male heterozygous for hairless is crossed with a hairy female heterozygous for long wings, what will be the phenotypic ratio of the F1? F2Phenotypes = 1/4 normal wings/hairless 1/4 normal wings/hairy 1/4 vestigial wings/hairless 1/4 vestigial wings/hairy = 1:1:1:1 ratio F1 Phenotypes = 1/4 normal wings/hairless 1/4 normal wings/hairy 1/4 vestigial wings/hairless 1/4 vestigial wings/hairy = 1:1:1:1 ratio F1 Genotypes = 1/4 NnHh 1/4 Nnhh 1/4 nnHh 1/4 nnhh = 1:1:1:1 ratio F1 Phenotypes = All normal wings/hairy = 1:0 ratio
- 4:12 8. A heterozygous round seeded plant (Rr) is crossed with a homozygous round seeded plant (RR). Give the expected probabilities for each genotype and phenotype. 9. A homozygous round seeded plant is crossed with a homozygous wrinkled seeded plant. What are the genotypes of the parents? X 10. In pea plants purple flowers are dominant white flowers. If two white flowered plants are crossed, what percentage of their offspring will be white flowered? % Previous What percentage of the offspring will also be homozygous? ZOOM + 12. Two plants, both heterozygous for the gene that controls flower color are crossed. Give the expected RATIOS for each genotype and phenotype. Phenotype Ratio - Gentoype Ratio - 11. A white flowered plant is crossed with a plant that is heterozygous for the trait. What percentage of the offspring will have purple flowers? 13. In guinea pigs, the allele for short hair is dominant over long hair. Two short haired guinea pigs are mated several times. Out of 100…dd-ons Help в I U A Calibri 12 三 三1 |:三 6. Consider a guinea pig with a homozygous genotype and a white fur color phenotype. a. What is the probability this parent will produce a gamete with the dominant allele? b. What is the probability this parent will produce a gamete with the recessive allele? C. If 31 sperm cells are collected from this guinea pig, how many would you expect to have the recessive allele (as determined by sequencing the gene)? !!!In sweet pea plants, an allele for purple flowers. (P) is dominanl when paired with a recessive allele for red flowers (p). An allele for Jang pollen grains (L) is dominant when paired with a recessive allele for round pollen grains (L). Bateson and Punnett crossed a plant having purple flowers and long pollen grains with one having white flowers and round pollen grains. All F1 offspring have purple flowers and long pollen grains. Among the F2 generation, the researchers observed the following phenotypes: 296 purple flowers/long pollen grains 19 purple /lower/ round pollen grains 27 red flowers/long pollen grains 85 red flowers/round pollen grains What is the best explanation for these results?
- 1-Show the results of a dihybrid cross for the F1 and F2 generation between P generation of a pea plant that is homozygous dominant for purple flower and yellow pea seed with another pea plant that is homozygous recessive for white flower and green pea seed. Clearly show the cross indicating BOTH genotype and phenotype for each generation. How many offspring in the F2 generation will have these phenotypes? 2-What is the probability of a woman who is a carrier for the blood disease hemophilia producing a son with hemophilia if she marries a man who does not have hemophilia? What is the probability of her daughters having hemophilia? Explain why the probability of getting this disease is different for sons versus daughters in this case. Your work should clearly indicated sex, genotype and phenotype (carrier or affected).Choice 2: Black versus orange fur is determined by two alleles an X-linked gene (XⓇ, Xº), Suppose that a black male is mated with an orange female. a) Write the genotypes of the male and female cats. Male: Female: b) What genotypes & phenotypes are expected among the offspring (F1) of these parent cats? c) Suppose that a male and a female from part b mate. What offspring types will they produce?(Purple) (White) 12. Two plants, both heterozygous for the gene that controls flower color are crossed. Give the expected RATIOS for each genotype and phenotype. Phenotype Ratio - Gentoype Ratio - 13. In guinea pigs, the allele for short hair is dominant over long hair. Two short haired guinea pigs are mated several times. Out of 100 offspring, 25 of them have long hair. What are the probable genotypes of the parents? (Show the cross to prove it!)
- 7-8. Assume that white color is dominant over yellow color in squash. If pollen from the anthers of a heterozygous white-fruited plant is placed on the pistil of a yellow- fruited plant, show using ratios the genotypes and phenotypes you would expect the seeds from this cross to produce. Genotypes = 1/2 Ww 1/2 Ww = 1:1 ratio | Phenotypes = All white = 1:0 ratio Genotypes = 1/2 WW 1/2 ww = 1:1 ratio | Phenotypes = 1/2 white 1/2 yellow = 1:1 ratio Genotypes = 3/4 Ww 1/4 ww = 1:1 ratio | Phenotypes = 3/4 white 1/4 yellow = 1:1 ratio Genotypes = 1/2 Ww 1/2 ww = 1:1 ratio | Phenotypes = 1/2 white 1/2 yellow = 1:1 ratioa. genotype of the parents b. Punnett square C. genotypic ratio с. d. phenotypic ratio e. type of Mendelian or non-Mendelian principle8-9. White eyes (w) is sex-linked and recessive in Drosophila. Cruved wings(cu) and black body (b) are autosomal recessive alleles on the same chromosome, separated by 20 map units. If one breeds a homozygous white, curved winged female fly to a homozygous black male fly to produce an F1, and inbreeds the F1 males and females, at what frequency is a phenotypically wild-type male expected? (note: male flies do not cross over) A. 0.25 es B.0.05 C.0.10 D. 0.20 E.0.125