62° with the direction of the magnetic field at the particle's location. The magnitude of the field is 0.230 T. (a) What is the magnitude of the magnetic force (in N) on the particle? (b) What is the magnitude of the particle's acceleration (in m/s2) at this instant?
62° with the direction of the magnetic field at the particle's location. The magnitude of the field is 0.230 T. (a) What is the magnitude of the magnetic force (in N) on the particle? (b) What is the magnitude of the particle's acceleration (in m/s2) at this instant?
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter30: Magnetic Fields And Forces
Section: Chapter Questions
Problem 43PQ
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Question
An alpha particle has a positive charge that is double the charge of a proton, and a mass of 6.64 ✕ 10−27 kg. At a particular instant, it is moving with a speed of 5.00 ✕ 106 m/s through a magnetic field. At this instant, its velocity makes an angle of 62° with the direction of the magnetic field at the particle's location. The magnitude of the field is 0.230 T.
(a)
What is the magnitude of the magnetic force (in N) on the particle?
(b)
What is the magnitude of the particle's acceleration (in m/s2) at this instant?
Expert Solution
Step 1
Magnetic force is always perpendicular to the velocity of the particle as well as the magnetic field.
FB =qv×B
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