5 kN 2 8 kN/m 5 kN-m -2 m- 2 m- onstruct the shear and bending moment diagrams. reactions: on the left is 29 kN up and on the right 5 kN-m 2 m- 5 kN -2 m-
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- Use the graphical method to construct the bending-moment diagram and identify the magnitude of the largest moment (consider both positive and negative). The ground reactions and the shear-force diagram are provided. M = 13 kN-m Ay = 3.46 KN Dy Units: KN = 32.54 kN M 4 m 29.5 kN-m 43.3 kN-m 25.8 kN-m O 22.9 kN-m 31.48 kN-m B Ay 4 m 15 kN C Ay 4 m Ay-15 7 kN/m D 3 m 21 Ay-15 E XUse the graphical method to construct the bending-moment diagram and identify the magnitude of the largest moment (consider both positive and negative). The ground reactions are provided. MB = 143 kN-m Mc = 51 kN-m Ay = 16.17 kN (down) Dy = 16.17 kN (up) 1997 4 m 5 m O 80.9 kN-m O 74.1 kN-m O 94.5 kN-m O 50.4 kN-m O 60.6 kN-m 3 m D Xplease draw a shear diagram and a moment diagram No elements selected 150 lb-ft V, lb 3000 2500 2000 1500 1000 500 0 0 -500 -1000 -1500- -2000 -2500 -3000 250 lb/h 20 ft 10 20 150 lb-ft z, ft
- 5 kN 5 kN 8 kN/m 5 kN-m 5 kN-m - 2 m- -2 m - 2 m - 2 m A) Construct the shear and bending moment diagrams. The reactions: on the left is 29 kN up and on the right is 13 kN up.Q4:Draw the shear force and bending moment diagram for beam shown below. A 3 15 KN 3 m 6 m 9 m BSolve for the reactions and draw the shear and moment diagram. 10 kN-m 2 kN/m 4 m 6 m 4 m 6 m 2 kN/m 10 kN | 5@2 m = 10 m 5@2 m = 10 m 10 kN-m 10 kN 5 m 5 m 5 m 5 m 10 kN-m 10 kN 5 m 5 m 5 m 5 m
- Use the graphical method to construct the bending-moment diagram and identify the magnitude of the largest moment (consider both positive and negative). The ground reactions and the shear-force diagram are provided. M= 12 kN-m Ay = 3.37 kN Dy = 32.63 kN | 15 kN M 7 kN/m В C D E 4 m 4 m 4 m 3 m 21 Ay Ay A, A,-15 A,-15 O 23.3 kN-m O 26.1 kN-m O 19.7 kN-m O 31.56 kN-m 29.6 kN-m Units: kNKe-45 Homework-3- 1. Calculate the moment at point (A) of the forces shown in figure. T;-10 2.5 m 1-25 m-I T-3N --- T T3=6 N M=5 N.m T=4 N T;=2 N 0=45° 3 m 5 m 2. Determine the moment of a 90 N force about point C for the condition 0 = 15°. 600mm A 90N 3. Find the forces in member AB and BC by component method. A TAK Tc 45 30 45° 30° Ring Pulley 60° 200 N Pulley 200 N 200 N 200 N 800mmFind the moment about A & B, where AB = AD = 12 m, F1= 4 N, F2 = 8 N, F3 = 13 N & F4 = 19 N. Each force is acting at the mid-point of each side. -- 4 Marks %3D %3D F1 F2 F4 D F3 (NOTE: ENTER ONLY THE VALUES BY REFERRING TO THE UNITS GIVEN IN THE BRACKET. ALSO, SUBMIT THE HANDWRITTEN ANSWER SHEET IN THE LINK PROVIDED) The moment of force about "A" (in Nm) (2 Marks) %3D The moment of force about "B" (in Nm) = (2 Marks) %3D
- Homework-3- 1. Calculate the moment at point (A) of the forces shown in figure. T;=10 2.5 m_-4 2.5 m - "-I T=3N т T3=6 N M=5 N.m T-4 N T3=2 N 0-45° 3 m 5 m 2. Determine the moment of a 90 N force about point C for the condition 0 = 15°. 600mm 9ÓN 3. Find the forces in member AB and BC by component method. C Tc 45 30 45° 30 Ring Pulley 60YB 200 N Pulley 200 N 200 N 200 N 4. Choose any question from (Ɛ ) and solve it as homework. 800mmDetermine the shear force V in the beam at a point located 3.00 ft to the left of point B. The ground reactions are provided. Ay = 2,635.7 lb By = 4,864.3 lb 1,200 lb 450 lb/ft B C 14 ft 6 ft O -2491 lb O -1663 lb O -1461 Ib O -2314 lb O -1905 lb%A I. Untitled Section F1 F2 a C F3 A b a F4 D E B Consider the following values: - F5 a = 16 m; b = 11 m; c = 13 m; d = 8 m; F1 - 3 kN; F2 - 11 kN; F3 - 2 kN; F4 - 20 kN; F5 - 2 KN; a = 30°, 0 = 60° , B= 30° 11 What is the resultant moment of the five forces acting on the rod about point A? a) 88.8 kN.m b) 76.3 kN.m c) 19.6 kN.m d) 55.5 kN.m e) 59.1 kN.m f) 81.3 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 88.8 kN.m b) 120.8 kN.m c) 31.6 kN.m d) 98.9 kN.m e) 41.1 kN.m f) 24.2 kN.m 31 What is the resultant moment of the five forces acting on the rod about point C? a) 125.7 kN.m b) 178.1 kN.m c) 254.6 kN.m d) 439.1 kN.m e) 144.1 kN.m ) 215.3 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) 77.8 kN.m b) 98.3 kN.m c) 100.6 kN.m d) 18.9 kN.m e) 97.1 kN.m H 60.1 kN.m 5] What is the moment of the force F2 about point E? c) 66.6 kN.m Activate W f) 151.3 kN.m a) 122.7 kN.m b) 108.1 kN.m d) 83.1 kN.m e)…