4. Complex inheritance: Remember there are some exceptions to Mendels laws such as incomplete dominance (hint a blending), codominance (hint: both traits show). Use this information to answer the following questions. e. A lily flower species contains 3 possible colors: blue (BB), red (RR), and purple (BR). What type of inheritance pattern is this? Incomplete Dominance f. If a red flower and purple flow are crossed what percent of the flowers would be red? Complete a punnett square to prove your answer. g. A man with type B blood marries a woman with type AB blood. Based on what you know about blood types, what is the only blood type not possible in any of their children? (remember you need to do two punnett squares to answer this) WATCH REVIEW VIDEO: Blood Types Parent Cross Blood Tune that is not possible (supported by evidence in crosses above) F1 Cross

4. Complex inheritance: Remember there are some exceptions to Mendels laws such as incomplete dominance (hint a blending), codominance (hint: both traits show). Use this information to answer the following questions. e. A lily flower species contains 3 possible colors: blue (BB), red (RR), and purple (BR). What type of inheritance pattern is this? Incomplete Dominance f. If a red flower and purple flow are crossed what percent of the flowers would be red? Complete a punnett square to prove your answer. g. A man with type B blood marries a woman with type AB blood. Based on what you know about blood types, what is the only blood type not possible in any of their children? (remember you need to do two punnett squares to answer this) WATCH REVIEW VIDEO: Blood Types Parent Cross Blood Tune that is not possible (supported by evidence in crosses above) F1 Cross

Name: 4. Complex inheritance: Remember there are some exceptions to Mendels
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Description: 4. Complex inheritance: Remember there are some exceptions to Mendels laws such as incompletedominance (hint a blending), codominance (hint: both traits show). Use this information toanswer the following questions.e. A lily flower species contains 3

Biology 2e

2nd Edition

ISBN:9781947172517

Author:Matthew Douglas, Jung Choi, Mary Ann Clark

Publisher:Matthew Douglas, Jung Choi, Mary Ann Clark

Chapter12: Mendel's Experiments And Heredity

Section: Chapter Questions

Problem 24CTQ: Mendel performs a cross using a true-breeding pea plant with round, yellow seeds and a true-...

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, Σ. K Q R. click "Turn In" on Google Classroom when you are done. 2. In pea plants, yellow seeds are dominant to green seeds. A heterozygous yellow-seeded pea plant (Yy) is crossed with a plant that has green seeds (yy). Yellow Seeds Y y Phenotype Probability (%) У Yellow Seeds: y Green Seeds: 4. In another one of Mendel's experiments. he crossed the offsprina. Two nea Hide sid US 12 Green Seeds 田

BIU A- == 三E 12 - Match each of the following examples to the appropriate type of non-Mendelian inheritance. 1. A homozygous recessive genotype for the gene that encodes phenylalanine hydroxylase (which breaks down the amino acid phenylalanine) causes lighter skin color, a musty odor, differences in intellectual development, and seizures. 2. In pea plants, alleles of Gene W control flower color, with the dominant allele (W) leading to purple flower.color, and the recessive allele (w) leading to white flower color. Usually, a genotype of WW or Ww leads to purple flowers. However, when Gene C is homozygous recessive, WW or Ww plants always have white flowers. 3. In mallard ducks, feather coloring is controlled by Gene F. A dominant allele (F) leads to green head feathers, while a recessive allele (f) leads to brown head feathers. In male mallards, inheritance of one or more F alleles always leads to the green head feather trait. But female mallards always have brown head feathers,…
CO-DOMINANCE/I... % Ø Oll ^ 6- 3. A homozygous red gummy bear is crossed with a homozygous yellow gummy bear (red and yellow mixed together make orange). You predicted that all the offspring will be orange gummy bears. Create a Punnett Square, then explain if your prediction was correct. 13 r y 2 / 3 | - h ? & 71 u * 82 87% i + | © k ( 93 O D § ) 014 Р 11 -½ { [ [ ^ 11 = ¾ 11 8 '{' \
O e. Parent 2: Parent 1: Parent 2: ¡Ai QUESTION 9 Bi QUESTION 8 Let's assume that, in dragons, red scales (B) are dominant to green scales (b), and long tongues (S) are dominant to short tongues (s). The genes that determine these characteristics assort independently. A homozygous red, long-tongued dragon is crossed with a homozygous green, short-tongued dragon. If an F1 dragon is crossed to a homozygous green and homozygous short-tongued dragon, what phenotypes and proportions are expected in the offspring? O a. 100% green and long-tongued O b. ½ green and short-tongued & ½ red and long-tongued O c. ½ red and short-tongued & ½ green and long-tongued O d.% red and long-tongued, % red and short-tongued, ½ green and long-tongued, % green and short-tongued O e. 9/16 red, long-tongued, 3/16 green, long-tongued, 3/16 red, short-tongued, 1/16 green, short-tongued Save and Submit to save and submit. Click Save All Answers to save all answers. 000 MacBook Air
From DNA to Protein and Inheritance Co-Dominance: In co-dominance, the heterozygous individual exhibits the phenotype for both alleles. We used the ABO blood groups as an example of co-dominance. 8. What potential blood types can be present in the offspring if two type "O" mate with one another? (alams 1) Ilgq xal Ligg 9. What are the potential blood types present in the offspring if two parents with type A blood mate with each other? parents 10. What are the potential blood types for offspring that are produced by a parent that is A+ and one that is AB-? Sgningatlo odi nol om sig gonda borooqxs Post-Lab Questions 1. In the human species, polydactyly (the
Inheritance of multiple genes: 8. A pure-bred grey cat mates with a pure-bred chocolate cat: a. What are the possible phenotypes of their kittens? b. For each of these phenotypes, what is their probability? black [Choose ] [Choose ] 0.75 gray 0.5 0 1.0 0.25 chocolate [Choose ] lilac [Choose ] cinnamon [Choose ] fawn [Choose ] orange [Choose ] cream [Choose ]
5. Flower position, stem length, and seed shape are three characters that Mendel studied. Each is controlled by an independently assorting gene and has dominant and recessive expression as nas indicated in Table 14.1. If a plant that is heterozygous for all three characters is allowed to self-fertilize, what proportion of the offspring would you expect to be each of the following? (Note: Use the rules of probability instead of a huge Punnett square.) (a) homozygous for the three dominant traits ndi Jou each er h (b) homozygous for the three recessive traits (c) heterozygous for all three characters ts is (d) homozygous for axial and tall, heterozygous for seed shape voul
B. Solve the following problems in non-Mendelian inheritance using the Punnett square. 1. Butterflies come in different colors. Some of them exhibit incomplete dominance. The three colors that show this trait are dark blue (B), white (W), and light blue (BW). Find the following: a. Genotypic and phenotypic ratios when a dark blue butterfly is crossed with a light blue butterfly b. Genotypic and phenotypic ratios of the F, generation when dark blue and white butterflies are crossed
Mendel is growing flowers. Pure red flowers have a pair of R genes. Pure whiteflowers have a pair of w genes. Red is dominant to white.(a) Write the Punnett square with a pure red parent cross-fertilized with a pure white parent.(b) Write a second Punnett square of the offspring of the preceeding question cross-fertilizedwith a pure white flower.(c) What is the probability that a flower from the second fertilization is pure white? (Writethe probability as a fraction in reduced form.)
Mendel's P1 Dihybrid Cross First parental (P1) generation WWGG wWgg Gametes WG Wg First filial (F1) generation Genotype Phenotype g bns es WwGg round and yellow- seeded plants Figure 1.3 Activity 4. SELF-CHECK 1. Based on the reșults of the dihybrid cross, can you tell which traits are dominant? Recessive? The P1 dihybrid cross is illustrated in Figure 1.3. Study it carefully. Capital letter W represents round pea seed which is dominant over wrinkled pea seed (w). Second parental (P2) generation (F1 self-pollinated) Ww Gg WwGg WG riWg WG of WG Gametes wG wG wg wg Second filial (F1) generation WG Wg wG to vitnsb Male wg Female WwGg 4 8 WWGg 2 wwgg 6 WwGg 10 14 WG WWGG 1 WWGG 3 Wg wG wWGg 5 WwGg 9 WwGg 13 WwGg 7 wwGg 11 wwGg 15 Wwgg wwGg 12 16 Wg Wwgg wwgg 2WwGg 4WwGg 2Wwgg Genotypic ratio 1 WWGG 2 WWG9 1WWgg 1wwGG 2wwGg 1wwgg
K M Q R T. e to click "Turn In" on Google Classroom when you are done. sed 2. In pea plants, yellow seeds are dominant to green seeds. A heterozygous yellow-seeded pea plant (Yy) is crossed with a plant that has green seeds (yy) Yellow Seeds Y y Phenotype Probability (%) y Yellow Seeds: y Green Seeds: d nea 4. In another one of Mendel's exneriments. he crossed the offsprina. Two pea US Green Seeds
1. Mendel crossed a plant that was heterozygous for height and heterozygous for pea shape with a plant that was homozygous dominant for height and heterozygous for shape. What are the possible genotypes and phenotypes of the offspring? Dominant for height= T (tall) Recessive for height =t (short) pea Dominant for pea shape = R (round) %3D Recessive for pea shape =r(wrinkled) P1: